All categories

3 years ago

Which equation describes the line containing the points (-2, 3) and (1, 2)

Physics

1 answer:

snow_lady [41]3 years ago

8 0

Answer:

$y = \frac{ - 1}{3}x + \frac{7}{3}$

Explanation:

$\frac{y - 3}{2 - 3} = \frac{x + 2}{1 + 2} \\ \ - y + 3 = \frac{x + 2}{3} \\ y = \frac{ - 1}{3}x + \frac{7}{3}$

You might be interested in

What is the net force? <br><br> URGENT! thank you

alexandr402 [8]

Net force is the vector sum of forces acting on a particle or body. The net force is a single force that replaces the effect of the original forces on the particle's motion. It gives the particle the same acceleration as all those actual forces together as described by the Newton's second law of motion.

6 0

4 years ago

State the laws of vibration of a stringed Instrument

olchik [2.2K]

If the length and linear density are constant, the frequency is directly proportional to the square root of the tension.

7 0

3 years ago

Who invented abstract geometry

Brrunno [24]

Wassily Kandinsky invented abstract geometry :) have a good week

6 0

3 years ago

Read 2 more answers

The magnetic flux through a metal ring varies with time t according to ΦB = at3 − bt2, where ΦB is in webers, a = 6.00 Wb s−3, b

pychu [463]

To solve this problem it is necessary to apply the second derivative of the function to find the maximum time reference and thus calculate the maximum voltage.

With the maximum voltage by Ohm's Law it is possible to find the maximum current.

Ohm's law defines that

E = I*R

Where,

I = Current

R= Resistance

On the other hand by faraday studies and the potential can be expressed at the rate of change of the electric flow, that is

$E = \frac{d\phi}{dt}$

Replacing with our values we have that

$E = \frac{d(6t^3-18t^2)}{dt}$

$E = -18t^2 +36t$

The second derivative is

$E' = -36t+36$

When E' = 0 we have a Maximum, then

0 = -36t+36

t = 1

Therefore when the time is 1s E has a Maximum, replacing at the function

$E(t) = -18t^2 +36t$

$E(1) = -18(1)^2 +36(1)$

$E = 18V$

Then the maximum current will be given by

$I = \frac{E}{R}$

$I = \frac{18}{2.8}$

$I = 6.42A$

Therefore the maximum current induced in the ring is 6.42A

6 0

4 years ago

A circuit consists of a coil that has a self-inductance equal to 4.3 mH and an internal resistance equal to 16 Ω, an ideal 9 V b

fredd [130]

Answer:

t = 186.2 μs

Explanation:

Current in LR series circuit

$I(t) = I_{s}( 1 - e^{-Rt/L)}$ ----(1)

steady current = I_{s} = V/R

time constant = τ = $L/R =4.3 * 10^{-3} / 16\\$

= 0.268 ms

magnetic energy stored in coil = $U_{L} = \frac{1}{2}LI^{2}$

rate at which magnetic energy stored in coil= $\frac{d}{dt}U_{L} =\frac{d}{dt} \frac{1}{2}LI^{2} \\ = LI\frac{dI}{dt}\\$ ----(2)

rate at which power is dissipated in R:

$P = I^{2}R$ ---(3)

To find the time when the rate at which energy is dissipated in the coil equals the rate at which magnetic energy is stored in the coil equate (2) and (3)

$I^{2}R=LI \frac{dI}{dt}$