All categories

2 years ago

Define 1 calorie heat

Physics

2 answers:

masha68 [24]2 years ago

8 0

Answer:

"One calorie of heat is defined as the amount of heat needed to raise the temperature of one gram of water by one degree Celsius"

Hope this Helps!

katrin2010 [14]2 years ago

6 0

Explanation:

One calorie of heat is defined as the amount of heat needed to raise the temperature of one gram of water by one degree Celsius (or one kelvin).

You might be interested in

How dose an atom become an ion with a -2 charge?

Aloiza [94]

A atom can become an ion with a -2 charge, if it gains 2 electrons during a chemical reaction.

6 0

4 years ago

What is the name given to the force exerted by the first object on a second object

Andre45 [30]

Soppose the 1 object is A and 2 is B then the force exerted by A on B is FAB and the force exerted on body B on A is -FAB.

6 0

4 years ago

Which list is in order from smallest to biggest

wel

Answer:

Explanation:

the solar system is smaller then nebula nebula is smaller then a galaxie and a galaxie is smaller then a universe

8 0

3 years ago

the guage pressure in a car tire is 30.0 psi when the air temperature is 0 C as the day warms up and brighten sun shines What is

Viktor [21]

Answer:

$P_2 = 33.297\ psi$

Explanation:

give,

Gauge pressure of car, P₁ = 30 psi

temperature,T₁ = 0° C = 0 + 273 = 273 K

Assuming temperature at the noon = 30° C

T₂ = 30 + 273 = 303 K

Pressure at this temperature, P₂ = ?

Using ideal gas equation

$\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}$

taking volume as in compressible V₁ = V₂

$\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}$

$\dfrac{30}{273}=\dfrac{P_2}{303}$

$P_2 = 303\times \dfrac{30}{273}$

$P_2 = 33.297\ psi$

Hence, Pressure of the at 30°C is equal to 33.297 psi.

3 0

3 years ago

A straight line is drawn on the surface of a 14-cm-radius turntable from the center to the perimeter. A bug crawls along this li

sleet_krkn [62]

Answer:

v = $\left[\begin{array}{c}0.66&0\end{array}\right]$ m/s

Explanation:

The position vector r of the bug with linear velocity v and angular velocity ω in the laboratory frame is given by:

$\overrightarrow{r}=vtcos(\omega t)\hat{x}+vtsin(\omega t)\hat{y}$

The velocity vector v is the first derivative of the position vector r with respect to time:

$\overrightarrow{v}=[vcos(\omega t)-\omega vtsin(\omega t)]\hat{x}+[vsin(\omega t)+\omega vtcos(\omega t)]\hat{y}$

The given values are:

$t=\frac{x}{v}=\frac{14}{3.8}=3.7 s$

$\omega=\frac{45\times2\pi}{60s}=4.7\frac{1}{s}$

8 0

3 years ago

Define 1 calorie heat​

Define 1 calorie heat