$\frac{ {7}^{4} ( - 2) {}^{4} {11}^{3} 6}{7 {}^{3} {2}^{2} {6}^{2} 11 {}^{2} } = \frac{7 \times {2}^{2} \times 11}{6} = \frac{308}{6} = \frac{154}{3} \\ \\ \frac{ {7}^{0} {12}^{0} {17}^{0} }{ {57}^{0} + ( {42}^{0} \times ( {13}^{0} ))} = \frac{1}{1 + 1} = \frac{ 1}{2}$

4 0

3 years ago

Negative three times a number is at least 57.

castortr0y [4]

The option formatting isn't very clear, anyway: given a number x, negative 3 times that number is -3x. If this has to be at least 57, it means that -3x must be greater than or equal to 57:

$-3x\geq 57$

Dividing both sides by -3 solves the equation, but we have to switch the inequality sign because we're dividing by a negative number:

$x\leq \dfrac{57}{3}=19$

4 0

3 years ago

After school, Tony biked toward the mountains at a constant rate of 8 mph. An hour later, Terry biked the same route at a consta

liberstina [14]

Answer: t-1

Step-by-step explanation: You’re welcome

7 0

3 years ago

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