The concentration of OH- ( symbol: [OH-] ), is equal to 10^-pOH (ten to the pOH'th power). The pOH equals 14 minus the pH, because the pH + the pOH = 14. So the pOH is 14-13= 1. Now the concentration of OH- is 10^-1 (= 1) moles/Litre
<span>NaOH (s) --> Na+ (aq) + OH- (aq) </span>
<span>1. : 1. : 1 </span>
<span>So by dissolving one mole of NaOH, you get one mole of Na+ and one mole of OH-. Meaning that the molarity (number of solved NaOH in one Litre) of NaOH is 1 mole/Litre, because the ratio is 1:1. This means, in ten litres of water there are also ten moles of NaOH. And the weight of one mole of NaOH is 40.00 grams (look it up in literature). So in ten litres solution with a pH of 13, there are 40.00*10 = 400 = 4 * 10^2 grams of NaOH dissolved</span>
Answer: False
Explanation:
Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.
Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.
Example: 
has similar molecular formula and empirical formula as the elements are already present in simplest of the ratios.
has molecular formula of but 
as the empirical formula.
At STP, 1 mol = 22.4
1 mol = 6.022 X 10^ 23
so your answer is right it is B 6.022 X 10^ 23
Answer:
The answer to your question is
51.- 1.59 x 10⁻⁶
53.- NaHCO₃ + HCl ⇒ H₂O + CO₂ + NaCl
Explanation:
51.- Convert 0.00159 ml to liters
Use a rule of three
1000 ml -------------- 1 l
0.00159 ml --------- x
x = (0.00159 x 1) / 1000
x = 0.00000159 l = 1.59 x 10⁻⁶ l
53.- Sodium hydrogen carbonate (NaHCO₃) reacts with hydrochloric acid to produce salt, water and carbon dioxide.
Sodium hydrogen carbonate = NaHCO₃
Hydrochloric acid = HCl
Reaction
NaHCO₃ + HCl ⇒ H₂O + CO₂ + NaCl
water = H₂O
carbon dioxide = CO₂
salt = NaCl
