Answer: V1 = 45.6 ml
Explanation:
This is a dilution process whereby the concentration of phosphate in the solution is being reduced from 4.5m to 2m. Meanwhile. In a concentration process, the concentration of the phosphate solution will be increased. It can be achieved by removing solvents.
The dilution equation will be used. The equation is as follows:
M1V1 = M2V2 where
V1 = Initial volume of phosphate solution.
M1 = Initial concentration of phosphate solution.
V2 =Final volume of phosphate solution.
M2 = Final concentration of phosphate solution .
From the information given,
M1 = 4.5
V1 = ?
M2 = 2.0
V2 = 80
4.5 × V1 = 2×80
4.5V1 = 160
V1 = 160/4.5
= 35.6 ml
Answer: What type of chemical reaction is rusting of iron?
Rust is formed when iron reacts with oxygen in moist air. The following chemical equation represents the reaction: 4Fe + 3O2 → 2Fe2O3. Water is necessary for the oxidation reaction to occur and to facilitate transport of the electrons.
Answer:
Excess reagent is the ZnS. After the reaction is complete, 1.67 moles of sulfide remain.
Explanation:
This is the reaction to work with:
2ZnS + 3O₂ → 2ZnO + 2SO₂
Limiting reagent is the oxygen. We confirm it by a rule of three
2 moles of sulfide can react to 3 moles of O₂
Therefore 3 moles of ZnS will react to (3 . 3) / 2 = 4.5 moles (we need 4.5 moles of O₂ and we only have 2 moles, that's why the O₂ is the limiting)
Excess reagent is the zinc (II) sulfide
3 moles of oxygen react to 2 moles of ZnS
2 moles of O₂ will react to (2 . 2) / 3 = 1.33 moles of ZnS (it is ok, be cause we have 3 moles, and we need only 1.33)
After the reaction is complete ( 3 - 1.33) = 1.67 moles of sulfide remain.
