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3 years ago

7. Convert 5.2 cm of magnesium (Mg) ribbon to mm of Mg ribbon.

Chemistry

2 answers:

Effectus [21]3 years ago

7 0

<h3>Answer:</h3>

52 mm

<h3>Explanation:</h3>

We are given;

5.2 cm of magnesium

Required to convert it to cm

We are going to use the appropriate conversion factor;

The units used to measure length include;

Kilometer(km)

Hectometer (Hm)

Decameter (dkm)

Meter(m)

Decimeter (dm)

Centimeter (cm)

Millimeter (mm)

Therefore; the appropriate conversion factor is 10mm/cm

Thus;

5.2 cm will be equivalent to;

= 5.2 cm × 10 mm/cm

= 52 mm

Therefore, the length of magnesium ribbon is 52 mm

luda_lava [24]3 years ago

5 0

Answer:

hey

Explanation:

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A sealed piston contains 400 mL of air at standard ambient pressure. The piston is

nydimaria [60]

Answer:

324.24 kPa

Explanation:

Given that;

Initial pressure P1 = 101325 Pa

V1= 400 ml

P2 = ?

V2= 125mL

From Boyle's law;

P1V1 = P2V2

P2 = P1V1/V2

P2= 101325 × 400/125

P2= 324.24 kPa

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3 years ago

14. What is the total number of kilojoules of heat needed to change 150. G of

Nadusha1986 [10]

Answer:

$\boxed {\boxed {\sf 50.1 \ kJ}}$

Explanation:

When water changes from ice (solid) to water (liquid), it is melting or fusion. Therefore, we can use the following formula to find energy:

$q=mH_f$

where <em>q</em> is the energy, <em>m </em>is the mass, and <em>Hf</em> is the heat of fusion.

1. Define Values

The mass is 150 grams. The heat of fusion for water is 334 Joules per gram.

$m= 150 \ g \\H_f=334 \ J/g$

2. Calculate Energy

Substitute the values into the formula.

$q=150 \ g * 334 \ J/g$

Multiply. Note that the grams (g) will cancel each other out and leave Joules as our units.

$q=150 *334 \ J$

$q=50100 \ J$

3. Convert Units

We found the answer in joules, but the question asks for kilojoules, so we must convert.

There are 1000 Joules in 1 kilojoule. Therefore, we can divide the joules calculated by 1000.

$50100 \ J *\frac{1 \ kJ}{1000 \ J}$

$\frac{50100 \ kJ}{1000 \ }$

$50.1 \ kJ$

<u>50.1 kilojoules </u>are needed to change 150 grams of ice to water.

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A hot air balloon can have a volume of 2950 cubic meters (2.95 ✕ 106 liters) and operate at temperatures up to 250°F (121°C). As

TiliK225 [7]

Answer:

2.64 × 10⁶ g

Explanation:

We can find the mass of air using the ideal gas equation.

$P.V=n.R.T=\frac{m}{M} .R.T$

where,

P is the pressure (P = 1.00 atm)

V is the volume (V = 2.95 × 10⁶ L)

n is the number of moles

R is the ideal gas constant (0.08206atm.L/mol.K)

T is the absolute temperature (121°C + 273 = 394 K)

m is the mass

M is the molar mass (28.09 g/mol)

$m=\frac{P.V.M}{R.T} =\frac{1.00atm \times 2.95 \times 10^{6} L \times 28.97g/mol}{(0.08206atm.L/mol.K) \times 394 K } =2.64 \times 10^{6} g$

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3 years ago