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3 years ago

What is the volume of 70.0 g of ether if density os 0.70 g/mL

1 answer:

3 0

$D = m / V$

$0.70 g/mL = \frac{70.0g}{V}$

$V = \frac{m}{D}$

$V = \frac{70.0g}{0.70g/mL}$

$V = 100 mL$

hope this helps!

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A container is filled with oxygen gas, and the pressure of

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Answer:

77,007 Pa

Explanation:

Hello!

In this case, since the equivalence statement for atmospheres and pascals is:

1 atm = 101,325 Pa

We can set up the following conversion factor to obtain the pressure in pascals:

$0.760atm*\frac{101,325Pa}{1atm}\\\\=77,007Pa$

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2 years ago

If you were sitting near a gram of protactinium-234 and a gram of uranium-234, both solid materials, which would you consider mo

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aswer: protactinium-234 is more dang erous than uranium

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2 years ago

What is the theoretical yield of fluorenone if you oxidize 175 mg of fluorene?

My name is Ann [436]

Answer:

602 mg of CO₂ and 94.8 mg of H₂O

Explanation:

The yield is measured by the amount of each product produced by the reaction.

The chemical formula of fluorene is C₁₃H₁₀, and its molar mass is 166.223 g/mol.

The oxidation, also know as combustion, of this hydrocarbon is represented by the following balanced chemical equation:

$2C_{13}H_{10}+31O_2\rightarrow 26CO_2+10H_2O$

To calculate the yield follow these steps:

1. Mole ratio

$2molC_{13}H_{10}:31molO_2:26molCO_2:10molH_2O$

2. Convert 175mg of fluorene to number of moles

$175mg/times 1g/1,000mg=0.175g$

Number of moles = mass in grams / molar mass

$\text{number of moles}=0.175g/166.223g/mol=0.0010528mol$

3. Set a proportion for each product of the reaction

a) For CO₂

i) number of moles

$2molC_{10}H_{13}/26molCO_2=0.0010528molC_{10}H{13}/x$

$x=0.0010528molC_{10}H_{13}\times 26molCO_2/2molC_{10}H_{13}=0.013686molCO_2$

ii) mass in grams

The molar mass of CO₂ is 44.01g/mol

mass = number of moles × molar mass

mass = 0.013686 moles × 44.01 g/mol = 0.602 g = 602mg

b) For H₂O

i) number of moles

$0.0010528molC_{10}H_{13}\times10molH_2O/2molC_{10}H_{13}=0.00526molH_2O$

ii) mass in grams

The molar mass of H₂O is 18.015g/mol

mass = number of moles × molar mass

mass = 0.00526 moles × 18.015 g/mol = 0.0948mg = 94.8 mg

4 0

3 years ago

What is the answer to this

scoray [572]

The answer is 128.19

7 0

3 years ago

How many grams of glucose are needed to form 150g of ethanol?

Svetradugi [14.3K]

1 mole glucose gives 2 moles of ethanol

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=1227.30 gm or 1.23 Kg

6 0

3 years ago