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SIZIF [17.4K]
3 years ago
6

What is the molarity of a solution made by dissolving 1.25 mol of HCl in enough

Chemistry
1 answer:
Ronch [10]3 years ago
4 0

Answer:

Explanation:

C

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A student needs exactly 1 gram of baking powder to conduct an experiment. The balance reads 0.37 grams. How
sammy [17]

Answer:

B

Explanation:

If the student needs one gram but so far only has 0.37 grams, then the amount they need is the difference between what they need and how much they already have. 1-0.37=0.63 grams.

...which isn't actually an option because none of them have decimal points but I would say it is B anyway because it is the equivalent ratio and maybe there was a typo.

Hope this helped!

6 0
3 years ago
Read 2 more answers
A car is moving with the velocity of 20m/s. After 5 seconds it's velocity becomes 50m/s. Find its acceleration.​
irinina [24]

Answer:

6 m/s^2

Explanation:

a= (v2 - v1)/t

= (50-20)/5

=6

7 0
3 years ago
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Where can you find a polar ice biome that contains pack ice and no soil?
ycow [4]

Answer:

APEX answer North Pole

Explanation:

6 0
3 years ago
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As ___ increases,___ increases
Goshia [24]

Answer:

if the force applied increases

if the area of contact increases

Explanation:

8 0
2 years ago
Calculate ΔG o for the following reaction at 25°C: 3Mg(s) + 2Al3+(aq) ⇌ 3Mg2+(aq) + 2Al(s) Enter your answer in scientific notat
larisa [96]

Answer:

-3.7771 × 10² kJ/mol

Explanation:

Let's consider the following equation.

3 Mg(s) + 2 Al³⁺(aq) ⇌ 3 Mg²⁺(aq) + 2 Al(s)

We can calculate the standard Gibbs free energy (ΔG°) using the following expression.

ΔG° = ∑np . ΔG°f(p) - ∑nr . ΔG°f(r)

where,

n: moles

ΔG°f(): standard Gibbs free energy of formation

p: products

r: reactants

ΔG° = 3 mol × ΔG°f(Mg²⁺(aq)) + 2 mol × ΔG°f(Al(s)) - 3 mol × ΔG°f(Mg(s)) - 2 mol × ΔG°f(Al³⁺(aq))

ΔG° = 3 mol × (-456.35 kJ/mol) + 2 mol × 0 kJ/mol - 3 mol × 0 kJ/mol - 2 mol × (-495.67 kJ/mol)

ΔG° = -377.71 kJ = -3.7771 × 10² kJ

This is the standard Gibbs free energy per mole of reaction.

5 0
3 years ago
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