If the coulombs are supplied at 1.44 V, then 4.766 × 10¹¹ joules are produced.
(a) The reaction is
2H₂O + 2e⁻ → H₂ + 2OH⁻
According to the reaction, 2 moles of electrons flow per mole of reaction,
(b) Given
T = 25°C
Change Celsius into Kelvin
T = 25°C
= (25 + 273 ) K
= 298 K
<h3>What is Ideal Gas Law ?</h3>
It is expressed as
PV = nRT
Hence ,
n = ![\frac{PV}{RT}](https://tex.z-dn.net/?f=%5Cfrac%7BPV%7D%7BRT%7D)
= ![\frac{(12)(3.5.10^{6} )}{(0.082057)(298)}](https://tex.z-dn.net/?f=%5Cfrac%7B%2812%29%283.5.10%5E%7B6%7D%20%29%7D%7B%280.082057%29%28298%29%7D)
= 1.7176 ×10⁶ mole
Now, From the given reaction we can say that ,1 mole of H₂ is produced by 2 moles of electron
Hence, 1.7176 × 10⁶ mole of H₂ is produced by
= 2 × 1.7176 × 10⁶ moles of electron
= 3.435 ×10⁶ moles of electron
We know that
charge = moles of electron × F
= (3.435 ×10⁶ × 96500) C
= 3.31 × 10¹¹ C
(c) We know that,
Voltage =
= ![\frac{J}{C}](https://tex.z-dn.net/?f=%5Cfrac%7BJ%7D%7BC%7D)
1.44 V = ![\frac{energy}{3.31 . 10^{11} }](https://tex.z-dn.net/?f=%5Cfrac%7Benergy%7D%7B3.31%20.%2010%5E%7B11%7D%20%7D)
Energy = 1.44 V × 3.31 × 10¹¹ C
= 4.766 × 10¹¹ Joules
Thus from the above conclusion we can say that, coulombs are supplied at 1.44 V, then 4.766 × 10¹¹ joules are produced.
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Question : Car manufacturers are developing engines that use H₂ as fuel. In Iceland, Sweden, and other parts of Scandinavia countries, where hydroelectric plants produce inexpensive electric power, the H₂ can be made industrially by the electrolysis of water.
a) How many moles of electrons flow per mole of reaction ?
b) How many coulombs are needed to produce 3.53X10⁶ L of H₂ gas at 12.0 atm and 25°C.
c) If the coulombs are supplied at 1.44 V, how many joules are produced?