Question

2KI + Pb(NO3)2 → 2KNO3 + PbI2 Determine how many moles of KNO3 are created if 0.03 moles of KI are completely consumed.

Answer 1

2:2 so the same proportion 
0,03

Answer 2

Answer: The moles of potassium nitrate produced is 0.03 moles

Explanation:

We are given:

Moles of potassium iodide = 0.03 moles

For the given chemical reaction:

$2KI+Pb(NO_3)_2\rightarrow 2KNO_3+PbI_2$

By Stoichiometry of the reaction:

2 moles of KI produces 2 moles of potassium nitrate

So, 0.03 moles of KI will produce = $\frac{2}{2}\times 0.03=0.03mol$ of potassium nitrate

Hence, the moles of potassium nitrate produced is 0.03 moles