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3 years ago

2KI + Pb(NO3)2 → 2KNO3 + PbI2 Determine how many moles of KNO3 are created if 0.03 moles of KI are completely consumed.

Chemistry

2 answers:

ElenaW [278]3 years ago

6 0

2:2 so the same proportion
0,03

Ipatiy [6.2K]3 years ago

3 0

<u>Answer:</u> The moles of potassium nitrate produced is 0.03 moles

<u>Explanation:</u>

We are given:

Moles of potassium iodide = 0.03 moles

For the given chemical reaction:

$2KI+Pb(NO_3)_2\rightarrow 2KNO_3+PbI_2$

By Stoichiometry of the reaction:

2 moles of KI produces 2 moles of potassium nitrate

So, 0.03 moles of KI will produce = $\frac{2}{2}\times 0.03=0.03mol$ of potassium nitrate

Hence, the moles of potassium nitrate produced is 0.03 moles

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