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Dominik [7]
3 years ago
15

2KI + Pb(NO3)2 → 2KNO3 + PbI2 Determine how many moles of KNO3 are created if 0.03 moles of KI are completely consumed.

Chemistry
2 answers:
ElenaW [278]3 years ago
6 0
2:2 so the same proportion 
0,03

Ipatiy [6.2K]3 years ago
3 0

<u>Answer:</u> The moles of potassium nitrate produced is 0.03 moles

<u>Explanation:</u>

We are given:

Moles of potassium iodide = 0.03 moles

For the given chemical reaction:

2KI+Pb(NO_3)_2\rightarrow 2KNO_3+PbI_2

By Stoichiometry of the reaction:

2 moles of KI produces 2 moles of potassium nitrate

So, 0.03 moles of KI will produce = \frac{2}{2}\times 0.03=0.03mol of potassium nitrate

Hence, the moles of potassium nitrate produced is 0.03 moles

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Aluminum chloride can be formed from its elements:
saul85 [17]

<u>Answer:</u> The \Deltas H^o_{formation} for the reaction is -1406.8 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The chemical reaction for the formation reaction of AlCl_3 is:

2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3 (s)    \Delta H^o_{formation}=?

The intermediate balanced chemical reaction are:

(1) HCl(g)\rightarrow HCl(aq.)    \Delta H_1=-74.8kJ    ( ×  6)

(2) H_2(g)+Cl_2(g)\rightarrow 2HCl(g)    \Delta H_2=-185kJ     ( ×  3)

(3) AlCl_3(aq.)\rightarrow AlCl_3(s)    \Delta H_3=+323kJ     ( ×  2)

(4) 2Al(s)+6HCl(aq.)\rightarrow 2AlCl_3(aq.)+3H_2(g)    \Delta H_4=-1049kJ

The expression for enthalpy of formation of AlCl_3 is,

\Delta H^o_{formation}=[6\times \Delta H_1]+[3\times \Delta H_2]+[2\times \Delta H_3]+[1\times \Delta H_4]

Putting values in above equation, we get:

\Delta H^o_{formation}=[(-74.8\times 6)+(-185\times 3)+(323\times 2)+(-1049\times 1)]=-1406.8kJ

Hence, the \Deltas H^o_{formation} for the reaction is -1406.8 kJ.

6 0
3 years ago
The combustion reaction for methane is shown below:
horrorfan [7]

Answer:

P =  14.1 atm    

Explanation:

Given data:

Mass of methane = 64 g

pressure exerted by water vapors = ?

Volume of engine = 24.0 L

Temperature = 515 K

Solution:

Chemical equation:

CH₄ + 2O₂      →      CO₂ + 2H₂O + energy

Number of moles of methane:

Number of moles = mass / molar mass

number of moles = 64 g/ 16 g/mol

Number of moles = 4 mol

Now we will compare the moles of water vapors and methane.

              CH₄          :            H₂O  

                 1            :             2

                 4            :         2/1×4 = 8 mol

Pressure of water vapors:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

P = 8 mol × 0.0821 atm.L/mol.K× 515 K / 24.0 L

P = 338.25 atm.L/ /  24.0 L

P =  14.1 atm      

4 0
3 years ago
Which best describes teratogen
Readme [11.4K]
A teratogen is an exposure (substance, organism or process) in pregnancy that has a harmful effect on the fetus. Teratogens can be diseases, medications, drugs and environmental exposures.
6 0
3 years ago
Why do you think the atomic number is basically represented by the number of protons and not the number of electrons?
Naya [18.7K]

Answer:

The atomic number equals the charge on the nucleus. It therefore also equals the number of protons in the nucleus and also equals numerically the number of electrons in the neutral atom. i think so, hope this helps you

Explanation:

6 0
3 years ago
Sodium hydroxide (NaOH) and elemental sodium (Na)
Olegator [25]

Answer:

If the question is which can make a buffer, then NH3, NH4Cl should be correct. Because Ammonium (NH4) is conjugate acid of NH3 so they can form an equilibrium which is basically a buffer whose purpose is to resist pH change.

Explanation:

6 0
3 years ago
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