The balanced equation is
4Fe+3O₂⇒2Fe₂O₃
We know that the mole of Fe₂O₃ is 6, and since the ratio between oxygen and <span>Fe₂O₃ is 3:2, we can see that
3:2 = x:6 (3 oxygen moles can make 2 </span>Fe₂O₃ moles = x oxygen moles can make 6 <span>Fe₂O₃ moles)
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Multiply outside and inside (3*6 , 2*x) and put them on opposing sides of the equation
2*x = 3*6
2x=18
x=9
Therefore 9 moles of oxygen is needed.
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Answer:
Atomic mass of E is 128.24
Explanation:
- The percentage composition by mass of an element in a compound is given by dividing the mass of the element by the total mass of the compound and expressing it as a percentage.
- In this case; the compound Bi₂E₃
Percentage composition of bismuth = 52.07%
Percentage composition of E = 47.93%
Mass Bismuth in the compound is (2×208.9804) = 417.96 g
Therefore,
To calculate the atomic mass of E
52.07% = 417.96 g
47.93% = ?
= (47.93 × 417.96 ) ÷ 52.07 %
= 384.729
E₃ = 384.729
Therefore; E = 384.729 ÷ 3
= 128.24
The atomic mass of E is 128.24
Answer:
the entropy change for the surroundings when 1.62 moles of CH4(g) react at standard conditions is −8.343 J/K
Explanation:
The balanced chemical equation of the reaction in the question given is:
Using standard thermodynamic data at 298K.
The entropy of each compound above are listed as follows in a respective order.
Entropy of (CH4(g)) = 186.264 J/mol.K
Entropy of (O2(g)) = 205.138 J/mol.K
Entropy of (CO2(g)) = 213.74 J/mol.K
Entropy of (H2O(g)) = 188.825 J/mol.K
The change in Entropy (S) of the reaction is therefore calculated as follows:
= -5.15 J/mol.K
Given that :
the number of moles = 1.62 of CH4(g) react at standard conditions.
Then;
The change in entropy of the rxn 
= −8.343 J/K
There are actually three: One oxygen atom and two hydrogen atoms.
Answer:
See explanation
Explanation:
The drug thalidomide with molecular formula C13H10N2O4 was widely prescribed by doctors for morning sickness in pregnant women in the 1960s.
The drug was sold as a racemic mixture (+)(R)-thalidomide and (-)(S)-thalidomide.
Unfortunately, only the (+)(R)-thalidomide exhibited the required effect while (-)(S)-thalidomide is a teratogen.
This goes a long way to underscore the importance of separation of enantiomers in drug production.
Therefore, all the teratogenic effects observed when using the drug thalidomide was actually as a result of the presence of (-)(S)-thalidomide, the unwanted enantiomer.
