What question are you talking about?
Answer:
See below.
Explanation:
The mass of octane in the sample of gasoline is 0.02851 * 482.6 = 13.759 g of octane.
The balanced equation is:
2C8H18(l) + 25O2(g) ----> 16CO2(g) + 18H2O(g)
From the equation, using atomic masses:
228.29 g of octane forms 704 g of CO2 and 324.3 g of H2O
So the mass of CO2 formed from the combustion of 13.759 g of octane = (704 * 13.759) / 228.29
= 42.43 g of CO2.
Amount of water = 324.3 * 13.759) / 228.29
= 19.55 g of H2O.
Answer:
One
Explanation:
The formulas for the two acids are CH₃CH₂COO-H and CH₃CH₂CH₂COO-H.
The key factors to consider are the polarities of the C-H and O-H bonds.
A. C-H bonds
The difference in electronegativity is ΔEN =|2.55 - 2.20| = 0.35.
This difference of so small that we usually consider the C-H bond to be nonpolar.
It is extremely unlikely that a C-H bond will dissociate onto ions.
B. O-H bonds
The difference in electronegativity is ΔEN =|3.44 - 2.20| = 1.24.
Thus, an O-H bond is highly polar covalent — the bond has about 32 % ionic character.
It is much more likely that an O-H bond will go all the way and dissociate onto ions.
RCOOH + H₂O ⇌ RCOO⁻ + H₃O⁺
The Kₐ for an O-H bond is about 10⁴⁶ times that of a C-H bond.
Only the O-H bond of a carboxylic acid will dissociate,
Answer: H₃PO₄
Explanation: the number beside h is a 3
