All categories

3 years ago

Question 5 of 10

Chemistry

1 answer:

lesya [120]3 years ago

5 0

Chemical equation represents a redox reaction :

2Li + MgCl₂ → 2LiCl + Mg

<h3>Further explanation</h3>

The oxidation-reduction reaction or abbreviated as Redox is a chemical reaction in which there is a change in oxidation number

Reaction

2Li + MgCl₂ → 2LiCl + Mg

Oxidation is an increase in oxidation number, while reduction is a decrease in oxidation number.

Oxidation

$\tt Li\rightarrow Li^+(0~to~+1)$

Reduction

$\tt Mg^{+2}\rightarrow Mg(+2~to~0)$

You might be interested in

a certain compound was found to contain 54.0 g of carbon and 10.5 grams of hydrogen. its relative molecular mass is 86.0. find t

dexar [7]

Answer:

empirical formula = C3H7

molecular formula = C6H14

3 0

3 years ago

Why do you think different liquids have different freezing points

Ganezh [65]

I think that different liquids have different freezing points because every liquid consists of different atoms and different things that make up the atom causing them to have different freezing points.

5 0

3 years ago

An airplane travels 2100 km at 1000km/hE. It encounters a wind and slows to 800 km/h E for the next 1300 km. What is the average

Deffense [45]

Answer:

The average velocity of the airplane for this trip is 1684.21 km/h

Explanation:

Average velocity is the rate of change of displacement with time. That is,

Average velocity = $\frac{Displacement }{Change in time}$ = Δx / Δt = $\frac{x2 - x1}{t2 - t1}$

Now we will calculate the time taken by the airplane for the first motion before it encounters a wind.

From,

Velocity = $\frac{Distance traveled}{Time taken}$

Time = $\frac{Distance traveled}{Velocity}$

Therefore, Time = $\frac{2100km }{1000km/h}$

Time = 2.1h

This is the time taken before the airplane encounters a wind.

Hence, t1 = 2.1h

Now, For the time taken by the airplane when it encounters a wind

Also from,

Velocity = $\frac{Distance traveled}{Time taken}$

Time = $\frac{Distance traveled}{Velocity}$

Therefore, Time = $\frac{1300km }{800km/h}$

Time = 1.625h

Hence, t2 = 1.625h

Now, to calculate the average velocity

Average velocity = $\frac{x2 - x1}{t2 - t1}$

x1= 2100, x2= 1300, t1= 2.1h and t2= 1.625h

Hence, Average velocity = $\frac{1300 - 2100}{1.625 - 2.1}$

Average velocity = 1684.21 km/h

7 0

3 years ago

Which element would you expect to have properties similar to Chlorine (Cl)

jeyben [28]

Answer:

Iodine

Explanation:

It's in the same group as chlorine.

5 0

4 years ago

5. __NH3 + __O2 >>>>>__ NO +__ H20

inn [45]

2 NH3+ 2 O2 —> 2 NO+ 3 H2O

5 0

3 years ago