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Arte-miy333 [17]
3 years ago
8

Help quickly pleaaas

Chemistry
1 answer:
Tems11 [23]3 years ago
3 0

Answer:

chymotrypsin, cleaves peptide bonds selectively on the carboxylterminal side of the large hydrophobic amino acids such as tryptophan, tyrosine, phenylalanine, and methionine

Under certain conditions butane reacts with oxygen to form butanone which can be easily hydrogenated to butanol. Butene is easily made from butanol by elimination of water.

Explanation:

These are for the first too

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Equation balancing a. S(s) + O2(g) → SO3(8) b. 2Al(s) + 3C12(8) ► 2AICI,(s) E. 2NaOH(s) + H2SO,(ac) —Na,SO (ac) + H2O(1) d. CHg(
Debora [2.8K]

Answer:

a. S(s) + 3/2 O₂(g) → SO₃(g)

b. Al(s) + 3/2 Cl₂(g) → AICI₃(s)

c. 2 NaOH(s) + H₂SO₄(ac) → Na₂SO₄(ac) + 2 H₂O(l)

d. C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) +  4 H₂O(g)

Explanation:

We will balance the equation using the trial and error method.

a. S(s) + O₂(g) → SO₃(g)

1. We will balance O atoms by multiplying O₂by 3/2.

S(s) + 3/2 O₂(g) → SO₃(g)

b. Al(s) + Cl₂(g) → AICI₃(s)

1. We will balance Cl atoms by multiplying Cl₂ by 3/2.

Al(s) + 3/2 Cl₂(g) → AICI₃(s)

c. NaOH(s) + H₂SO₄(ac) → Na₂SO₄(ac) + H₂O(l)

1. We will balance Na atoms by multiplying NaOH by 2.

2. We will balance H and O atoms by multiplying H₂O by 2.

2 NaOH(s) + H₂SO₄(ac) → Na₂SO₄(ac) + 2 H₂O(l)

d. C₃H₈(g) + O₂(g) → CO₂(g) +  H₂O(g)

1. We will balance C atoms by multiplying CO₂ by 3.

2. We will balance H atoms by multiplying H₂O by 4.

3. We will balance O atoms by multiplying O₂ by 5.

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) +  4 H₂O(g)

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A company sells a natural medicine with plant ingredients to help treat dementia, a disease in which people have a hard time rem
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I think it is the second one. hope it helps! :)
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Which of the following best describes repulsions?
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A. to push each other away
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In nematode worms, a gene that codes for an ATPase has two alternatives for exon 4 and three alternatives for exon 7. How many d
Artyom0805 [142]

Answer:

6 different forms of the protein could be made.

Explanation:

For the given nematode worm, 6 different forms of the protein could be made. This is because of the alternative splicing that will produce 6 kinds of mRNAs. We have 2 different forms for the exon 4 while we have 3 differen forms for the exon 7. Therefore, we have a total of (2*3) 6 different forms of the protein for the given nematode worm.

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