The answer is not defined.
Explanation:
The given matrix is ![$\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]+\left[\begin{array}{c}{1} \\ {0}\end{array}\right]$](https://tex.z-dn.net/?f=%24%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%7B2%7D%20%26%20%7B4%7D%20%5C%5C%20%7B1%7D%20%26%20%7B-6%7D%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D%7B1%7D%20%5C%5C%20%7B0%7D%5Cend%7Barray%7D%5Cright%5D%24)
The matrix ![$\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]$](https://tex.z-dn.net/?f=%24%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%7B2%7D%20%26%20%7B4%7D%20%5C%5C%20%7B1%7D%20%26%20%7B-6%7D%5Cend%7Barray%7D%5Cright%5D%24)
has dimensions 
This means that the matrix has 2 rows and 2 columns.
Also, the matrix ![$\left[\begin{array}{l}{1} \\ {0}\end{array}\right]$](https://tex.z-dn.net/?f=%24%5Cleft%5B%5Cbegin%7Barray%7D%7Bl%7D%7B1%7D%20%5C%5C%20%7B0%7D%5Cend%7Barray%7D%5Cright%5D%24)
has dimensions 
This means that the matrix has 2 rows and 1 column.
Since, the matrices can be added only if they have the same dimensions.
In other words, to add the matrices, the two matrices must have the same number of rows and same number of columns.
Since, the dimensions of the two matrices are not equal, the addition of these two matrices is not possible.
Hence, the addition of these two matrices is not defined.
1)Parallel means they have to have the same slope. Since our equation is y=2/3x+1, a line parallel to that would be(using out points) -5=2/3(-4)+b.
To find the y-intercept, solve for "b".
b=-7/3
Our equation would then be y=2/3x-7/3
2)Perpendicular lines have opposite-reciprocal slopes. our previous equation was y=2/3x+1, so our new equation would be -5=-3/2(-4)+b. Now lets solve for b.
b=-11
So our perpendicular equation would be y=-3/2x-11
Hope that was helpful. :)
(a^3b)^2 • 4ab^3
a^6b • 4ab^3
4a^6b+1b^3
3*2 probably I’m sorry if it’s wrong
T5-24. T6-17. T7-10. T8-3........... it goes down by 7
