How to solve this: (in case you need it)
4n-18=52
4n-18+18=52+18
4n=70
4n/4=70/4
n=35/2
For this case we have to define trigonometric relations of rectangular triangles that:
- The cosine of an angle is given by the leg adjacent to the angle on the hypotenuse of the triangle.
- The sine of an angle is given by the leg opposite the angle on the hypotenuse of the triangle.
Then, according to the figure we have:
Answer:
Option D
Solve first equation for y:
5x+y=10
y=10-5x. Plug this equation into second equation
-x-(10-5x)=-2
-x-10+5x=-2
4x=8
x=2 (plug x into first equation)
5(2)+y=10
y=0
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
#SPJ1
