For this case we must solve the following equation:
So we have to:
Applying square root to both sides of the equation:
Thus, we have two roots:
Answer:
Kelly separated 618 cookies into baggies. Each baggie contained 3 cookies. How many baggies of cookies did Kelly make?
1 answer:
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Answer: x = 5π/6
Explanation:
1) Given function:
2) x-intercept are the roots of the function, i.e. the solution to y = 0
3) to find when y = 0, you can either solve the equation or look at the graph.
4) Solving the equation you get:
y = 0 ⇒ tan(x - 5π/6) = 0 ⇒ x - 5π/6 = arctan(0)
arctan(0) is the angle whose tangent is zero,so this is 0
⇒ x - 5π/6 = 0 ⇒ x = 5π/6.
Then, one example of an x-intercept is x = 5π/6, which means that when x = 5π/6, the value of the function is 0.
Since, the tangent function is a periodic function, there are infinite x-intecepts, that is why the questions asks for one example and not all the values.
You can verify by replacing the value x = 5π/6 in the given function:
y = tan (5π/6 - 5π/6) = tan(0) = 0.
Explanation:
1) Given function:
2) x-intercept are the roots of the function, i.e. the solution to y = 0
3) to find when y = 0, you can either solve the equation or look at the graph.
4) Solving the equation you get:
y = 0 ⇒ tan(x - 5π/6) = 0 ⇒ x - 5π/6 = arctan(0)
arctan(0) is the angle whose tangent is zero,so this is 0
⇒ x - 5π/6 = 0 ⇒ x = 5π/6.
Then, one example of an x-intercept is x = 5π/6, which means that when x = 5π/6, the value of the function is 0.
Since, the tangent function is a periodic function, there are infinite x-intecepts, that is why the questions asks for one example and not all the values.
You can verify by replacing the value x = 5π/6 in the given function:
y = tan (5π/6 - 5π/6) = tan(0) = 0.
Answer: a) 79.10 % b) 7% c)19.85 %
Step-by-step explanation:
a) Z = ( × - μ ) ÷ σ Where μ mean of population σ standard deviation Z is the abscissa to give the area or probability we are looking for associated to the value 10 ounces ( × )
So: Z = ( 10 - 9 ) ÷ 1.2 ⇒ Z = 1/1.2 ⇒ Z = 0.83 it has to be below this value
From Z tables we get P [ Z ≤ 0.82 ] = 0.7910 0r 79.10 %
b) Following the same procedure: We look for
P [ Z > ( x - μ ) ÷ σ ] ⇒ Z = ( 12 -10 ) ÷ 1.2 = 2.5
From Z table we get the area under the curve from the left tail up to the point Z < 2.5 ( 2.5 not included) but we were asked for the area out of that previous so 1- 0.9930 = 0.007 is the area we are looking for
So P (b) = 0.007 or 7 %
Finally between the two points above mentioned ( 10 ≤ Z ≤ 12 ) we use the previous values (taking in consideration the limits, according to the problem statement )
Z ≤ 10 Z ⇒( 10-9 ) ÷ 1.2 Z = 0.7967
Z ≥ 12 Z ⇒ ( 12 - 9 ) ÷ 1.2 Z = 0.9952
The interval is between these two points
0.9952 - 0.7967 = 0.1985 ⇒ or 19.85 %
The attached help in the understanding of the solution
