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4vir4ik [10]
4 years ago
14

Josh starts at a position of x=0 meters at the left side of the front of the classroom. Over the course of the class he walks ba

ck and forth in front of the class 15 times, 6 meters to the right, and then 6 meters back to the left. What is the total distance (in meters) Josh walks? (Enter just the number, no units.)
Physics
1 answer:
Aneli [31]4 years ago
3 0
Answer:
180 meters

Explanation:
Josh walks 6 meters to the right and the 6 meters back. This means that in one time, Josh walks a total distance of 6+6 = 12 meters
Now, we are given that Josh walks this same distance 15 times.
Therefore, we will multiply this distance by 15 to get the total distance that he walks as follows:
Total distance = 12*15 = 180 meters

Based on the above calculations, Josh walks 180 meters over the course of the class

Hope this helps :)
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GarryVolchara [31]

Distant objects in the universe moving away from Earth because the universe is expanding.

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3 years ago
An x-ray beam of a certain wavelength is incident on a crystal, at 30.7° to a certain family of reflecting planes of spacing 33.
klemol [59]

Answer:

λ=34.068pm

Explanation:

Wavelength λ=2dsinθ

λ=2(33.4pm)sin30.7

λ=2(33.4pm) * 0.510

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3 0
3 years ago
Read 2 more answers
A 2-kg wheel rolls down the road with a linear speed of 15m/s. Find its trwansitional and rotational kinetic energies.​
Elza [17]

Answer:

The translational kinetic energy is 225 J

The rotational kinetic energy is 225 J

Explanation:

Given;

mass of the wheel, m = 2-kg

linear speed of the wheel, v = 15 m/s

Transnational kinetic energy is calculated as;

E = ¹/₂MV²

where;

M is mass of the moving object

V is the velocity of the object

E =  ¹/₂ x 2 x (15)²

E = 225 J

Rotational kinetic energy is calculated as;

E = ¹/₂Iω²

where;

I is moment of inertia

ω is angular velocity

E = \frac{1}{2} I \omega^2\\\\E = \frac{1}{2} *mr^2*(\frac{v}{r})^2\\\\E =  \frac{1}{2} *mr^2*\frac{v^2}{r^2} \\\\E =  \frac{1}{2}mv^2

E =  ¹/₂ x 2 x (15)²

E = 225 J

Thus, the translational kinetic energy is equal to rotational kinetic energy

6 0
3 years ago
At a given location from a source charge, the electric field______________.a. strength is dependent on the source charge and the
noname [10]

Answer:

b. The electric field points away from the source charge, if the source charge is positive

d. The electric field points toward the source charge, if the source charge is negative.

Explanation:

A positive source charge would create an electric field that would exert a repulsive effect upon a positive test charge. Thus, the electric field vector would always be directed away from positively charged objects. On the other hand, a positive test charge would be attracted to a negative source charge. Therefore, electric field vectors are always directed towards negatively charged object.

Also electric field strength depends only on test charge

The correct options include b and d

The electric field points away from the source charge, if the source charge is positive.

Also, the electric field points toward the source charge, if the source charge is negative.

3 0
3 years ago
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