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4vir4ik [10]
4 years ago
14

Josh starts at a position of x=0 meters at the left side of the front of the classroom. Over the course of the class he walks ba

ck and forth in front of the class 15 times, 6 meters to the right, and then 6 meters back to the left. What is the total distance (in meters) Josh walks? (Enter just the number, no units.)
Physics
1 answer:
Aneli [31]4 years ago
3 0
Answer:
180 meters

Explanation:
Josh walks 6 meters to the right and the 6 meters back. This means that in one time, Josh walks a total distance of 6+6 = 12 meters
Now, we are given that Josh walks this same distance 15 times.
Therefore, we will multiply this distance by 15 to get the total distance that he walks as follows:
Total distance = 12*15 = 180 meters

Based on the above calculations, Josh walks 180 meters over the course of the class

Hope this helps :)
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Fifteen grams of substance X at 95 degrees Celsius is mixed with 45 grams of substance Z at 85 degrees Celsius in a container wh
Viefleur [7K]
According to the Law of Conservation of Energy, energy is neither created nor destroyed. They are just transferred from one system to another. To obey this law, the energy of the substances inside the container must be equal to the substance added to it. The energy is in the form of heat. There can be two types of heat energy: latent heat and sensible heat. Sensible heat is energy added or removed when a substance changes in temperature. Latent heat is the energy added or removed at a constant temperature during a phase change. Since there is no mention of phase change, we assume the heat involved here is sensible heat. The equation for sensible heat is:

H = mCpΔT
where
m is the mass of the substance
Cp is the specific heat of a certain type of material or substance
ΔT is the change in temperature.

So the law of conservation of heat tells that:

Sensible heat of Z + Sensible heat of container = Sensible heat of X

Since we have no idea what these substances are, there is no way of knowing the Cp. We can't proceed with the calculations. So, we can only assume that in the duration of 15 minutes, the whole system achieves equilibrium. Therefore, the equilibrium temperature of the system is equal to 32°C. The answer is C.
5 0
3 years ago
If a light ray from a candle strikes a mirror at an angle of 40° with the normal, at what angle will the ray reflect?. Select on
tekilochka [14]

Answer: The correct answer is option (C).

Explanation:

Law of reflection:

  • Angle of incident is equal to angle of reflection;∠i=∠r
  • Incident ray, reflected ray and normal to the reflecting interface at the point of incidence all lie in same plane.

When light ray from candle strikes a mirror at an angle of 40° with the normal, then the angle at which ray reflected back will 40°.


6 0
3 years ago
Read 2 more answers
I need help on this question please answer within like a PLEASE QUICK HELP
Ludmilka [50]
The answer is c 5 starrrrrr
7 0
3 years ago
At a pressure of one atmosphere methane boils at −161°C and freezes at −182.5°C. Consider a temperature scale where the boiling
lawyer [7]

Answer:

-421.627906977\^{\circ}M

Explanation:

Absolute zero in the Kelvin scale = -273.15 °C

Temperature difference in the boiling and freezing point

-161-(-182.5)=21.5\ ^{\circ}C

Change in 21.5°C = Change of 100°C in M

1^{\circ}C=\dfrac{100}{21.5}=4.6511627907\ ^{\circ}M

Difference in the Celsius scale

-182.5-(-273.15)=90.65\ ^{\circ}C

Change in 90.65\ ^{\circ}C corresponds to

4.6511627907\times 90.65=421.627906977\ ^{\circ}M

Therefore the absolute zero in the Methane scale is

-421.627906977\ ^{\circ}M

3 0
3 years ago
Object A has of mass 7.20 kilograms, and object B has a mass of 5.75 kilograms. The two objects move along a straight line towar
Vera_Pavlovna [14]
If the collision is elastic, there is no loss in kinetic energies, which means that the total energies before and after impact are the same.  So no need to worry about final velocities.

Final energy
= initial energy
= (1/2) (7.20*2.00^2+5.75*(-1.30)^2)
=19.26 joules

Answer: the total kinetic energy is 19.3 J. after collision.

8 0
4 years ago
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