Josh starts at a position of x=0 meters at the left side of the front of the classroom. Over the course of the class he walks ba
ck and forth in front of the class 15 times, 6 meters to the right, and then 6 meters back to the left. What is the total distance (in meters) Josh walks? (Enter just the number, no units.)
Explanation: Josh walks 6 meters to the right and the 6 meters back. This means that in one time, Josh walks a total distance of 6+6 = 12 meters Now, we are given that Josh walks this same distance 15 times. Therefore, we will multiply this distance by 15 to get the total distance that he walks as follows: Total distance = 12*15 = 180 meters
Based on the above calculations, Josh walks 180 meters over the course of the class
The velocity increased from 4 m/s to 22 m/s in 3 seconds. 18 m/s in 3 seconds so the average acceleration is change in velocity divided by time. 18 m/s divided by 3 seconds = 6 m/s^2
