Answer:
1200N/m
Explanation:
given parameters:
force on the motorcycle spring is 240N
Extension 2cm or 0.02m
unknown _
spring constant:
:?
solution:
to a spring a force applied is given as :
f=ke
f is applied as force
k is spring constant
e is the Extension
240= kx0.02
k=1200N/m
<span>An observation of the red shift of galaxies suggests that the universe is expanding. The correct option among all the options that are given in the question is the first option or option "a". I hope that this is the answer that you were looking for and it has actually come to your help.</span>
We anticipate a constant Poynting vector of magnitude since the hot resistor will be emitting heat and none of the electric or magnetic fields will change over time.
S = P/A
= I2R/ 2πrL
= 332 kW/m2
Always pointing away from the wire, this Poynting vector.
<h3>What is the Poynting vector?</h3>
Describes the size and direction of the energy flow in electromagnetic waves using a Poynting vector. It bears the name of the 1884 invention of English physicist John Henry Poynting. It stands for the electromagnetic field's directional energy flux or power flow. The Poynting vector is significant in a static electromagnetic field because it determines the direction of energy flow in an electromagnetic field. This vector represents the radiation pressure of an electromagnetic wave and points in its direction of propagation.
To learn more about Poynting vector, visit:
<u>brainly.com/question/17330899</u>
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Dispersion im pretty sure
Answer:
Option B.
Explanation:
Assuming the stick is in vertical position, its shadow depends on two factors: its length and the angle between the sun rays and the stick. When the angle is bigger, the lenght of the shadow increases, and vice versa. So, when the sun rays are parallel to the stick, the shadow may be small. Since they are nearly perpendicular to the Earth's surface at 12 o'clock, the shadow of the stick at that time should be minimal. It means that the measured shadow of 75 cm at 12:30 p.m. is almost impossible (Option B).
