Glucose is the starting molecule for glycolysis.
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Ca + H₃PO₄ → Ca₃(PO₄)₂ + H₂
Balance PO₄.
1 on the left, 2 on the right. Add a coefficient of 2 in front of H₃PO₄.
Ca + 2H₃PO₄ → Ca₃(PO₄)₂ + H₂
Balance H.
6 on the left, 2 on the right. Add a coefficient of 3 in front of H₂.
Ca + 2H₃PO₄ → Ca₃(PO₄)₂ + 3H₂
Balance Ca.
1 on the right, 3 on the right. Add a coefficient of 3 in front of Ca.
3Ca + 2H₃PO₄ → Ca₃(PO₄)₂ + 3H₂
Our final balanced equation:
3Ca + 2H₃PO₄ → Ca₃(PO₄)₂ + 3H₂
Hope this helps!
Answer:
First, find out how many moles of N2I6 you have. Then convert that to grams.
molar mass N2I6 = 789 g
moles N2I6 = 8.2x1022 molecules N2I6 x 1 mole/6.02x1023 molecules = 1.36x10-1 moles = 0.136 moles
grams N2I6 = 0.136 moles x 789 g/mole = 107 g = 110 g (to 2 significant figures)
Answer:
, the solution is basic
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
Acids have pH ranging from 1 to 6.9 and bases have pH ranging from 7.1 to 14.Neutral substances have pH of 7.
![pH=-\log [H_3O^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH_3O%5E%2B%5D)
![pOH=-\log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5BOH%5E-%5D)
Putting in the values:
![pOH=-\log[5.5\times 10^{-5}]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5B5.5%5Ctimes%2010%5E%7B-5%7D%5D)



![9.8=-\log [H_3O^+]](https://tex.z-dn.net/?f=9.8%3D-%5Clog%20%5BH_3O%5E%2B%5D)
![[H_3O^+]=1.6\times 10^{-10}M](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D1.6%5Ctimes%2010%5E%7B-10%7DM)
As pH is more than 7, the solution is basic
Answer: D
Explanation:
Chlorine is in group 7 or (VII) in Roman numerals, which means it has 7 balance electrons. It only needs one electron to become stable, hence it is next to the noble gases