Answer:
0.15 (M) of NaCl
Explanation:
An isotonic solution is defined as the solution having the same osmolarity, or the same solute concentration, as the another solution. If the two solutions are to be separated by any semipermeable membrane, then water will start flowing in equal parts from each solution and also into the other.
In the context, since it is given that the red blood cells exerts the same osmotic pressure as a 0.15 (M) of NaCl solution.
Thus, 0.15 (M) of NaCl is a isotonic solution.
Answer and explanation:
The attached figure shows five different structures for the chemical formula C4H5O5, but only one of these structures represent the malic acid.
Malic acid is a dicarboxylic acid, this means malic acid has two
-COOH groups. Also, malic acid is a secundary alcohol, which means it has a R2-C-OH group.
-Structure A has two carboxylic groups, but it doesn´t have a secundary alcohol.
-Structure B doesn´t have any caborxylic group.
-Structure C has two carboxylic groups and it is a secundary alcohol. Structure C is the Malic acid
<span>(NH4)2CO3 -> 96.09 g/mol
(6.995g ammonium carbonate)(1mol ammonium carbonate/ 96.09 g ammonium carbonate) = 0.072796 mol ammonium carbonate
In this conversion, the 'grams' unit is crossed out because it is in both the numerator and the denominator, which leaves the 'mol' unit left.
Looking at the formula (NH4)2CO3, you can look at it as if it were:
2 mol (NH4) + 1 mol (CO3) = 1 mol (NH4)2CO3
For every 1 mol of ammonium carbonate, you have 1 mol of carbonate ions and 2 moles of ammonium ions.
(0.072796 mol ammonium carbonate) = (0.072796 mol carbonate ion)+(0.363981 mol ammonium ion) </span>
Answer:
-173.15°C
Explanation:
Given data:
Temperature changes = 100 K
Temperature changes in degree Celsius = ?
Solution:
Kelvin and degree Celsius both are units of temperature.
In order to convert the degree Celsius to kelvin following equation is used.
Temperature in degree Celsius +273.15
For example;
100°C to kelvin = 100+273.15 = 373.15 K
To convert the kelvin into degree Celsius:
100K - 272.15 = -173.15°C
