I mostly believe in between D and B beacuse K3po4 and caco3 is not an element equation
The balanced chemical equation of the reaction described above is,
C2H6O + O2 --> H2O + C2H4O2
If we have 3.84 g of oxygen, we divide by its molar mass.
n = (3.54 g Oxygen gas) x (1 mole O2/ 32 g O2)
n = 0.11 moles O2
Using ratio and proportion,
number of moles of ethanol = (0.11 moles O2) x (1 mole C2H6)
= 0.11 moles C2H6
Then, we multiply the calculated value to its molar mass, 46 grams /mol.
mass of ethanol = (0.11 mol) x (46 grams / mol)
= <em>5.06 grams</em>
Ionic charge = +4
To answer this we look only at the protons and electrons. Because there are 4 more protons than electrons we know that this ion has 4 less electrons than it would need to have to have a neutral charge. Therefore, the ionic charge is +4
Answer:
8.5gm O2 produced
Explanation:
When heated, KClO3 decomposes into KCl and O2. 2KClO3⟶2KCl+3O2 If this reaction produced 13.2 g KCl, how many grams of O2 were produced?
for every 2 moles of KCl produced, 3 moles of O2 are produced
Mol weight of KCl =39+35.5=74.5gm
13.2 gm KCl = 13.2/74.5 = 0.177 moles
this will make (3/2) X 0.177 = 0.2655 moles of O2
O2 mol wt is 32 0.2655 X32 = 8.5gm O2 produced
