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Nutka1998 [239]
3 years ago
7

In ammonia, a central nitrogen atom is bonded to three hydrogen atoms. Similarly, boron trifluoride has a central boron atom bon

ded to three fluorine atoms. However, ammonia is pyramidal and boron trifluoride is trigonal planar in shape. Which statement justifies this difference in
their structure?

A.The lone pair of electrons in boron trifluoride increases the bond angle between the bonding pairs, giving it a planar structure.

B.The lone pair of electrons in boron trifluoride decreases the bond angle between the bonding pairs, giving it a planar structure.

C.The lone pair of electrons in boron trifluoride stabilizes the bond angle between the bonding pairs, giving it a planar structure.

D.The lone pair of electrons in ammonia increases the bond angle between the bonding pairs, giving it a pyramidal structure.

E.The lone pair of electrons on the nitrogen in ammonia decreases the bond angle between the bonding pairs, giving it a
pyramidal structure.
Chemistry
1 answer:
tankabanditka [31]3 years ago
4 0

Answer:

E.

Explanation:

E - The lone pair in the nitrogen atom squeezes the perfect tetrahedron  by a couple of degrees.

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A 29.05 gram sample of cobalt is heated in the presence of excess oxygen. A metal oxide is formed with a mass of 40.88 g. Determ
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The empirical formula of the oxide is Co₂O₃.

<em>Step 1</em>. Calculate the <em>mass of oxygen</em>

Your reaction is

 Cobalt + oxygen ⟶ cobalt oxide

29.05 g +    x g    ⟶     40.88 g

According to the <em>Law of Conservation of Mass</em>, the total mass of the reactants must equal the total mass of the products. Thus,

29.05 g + <em>x</em> g ⟶ 40.88 g

<em>x</em> = 40.88 – 29.05 = 11.83

<em>Step 2</em>. Calculate the <em>moles of each element</em>

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of Co to O.

<em>Moles of Co</em> = 29.05 g Co × (1 mol Co /(58.93 g Co) = 0.492 96 mol Co

<em>Moles of </em>O = 11.83 g O × (1 mol O/16.00 g O) = 0.739 38 mol O

<em>Step 3</em>. Calculate the <em>molar ratio</em> of the elements

Divide each number by the smaller number of moles

Co:O = 0.429 26:0.739 38 = 1:1.4999

<em>Step 4</em>. Multiply each number by a factor that makes the <em>ratio close to whole numbers </em>

Multiply by 2. Then

Co:O = 2:2.998 ≈ 2:3

<em>Step 5</em>: Write the <em>empirical formula</em>

EF = Co₂O₃

4 0
3 years ago
Is this true or false? :D
Valentin [98]

Answer:

true i am pretty sure

Explanation:

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