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3 years ago

6 1/5 + (-7 3/5)

1 answer:

5 0

Since you are subtracting a negative you can do it this way. do 7 3/5 - 6 1/5. that leaves you with 1 2/5. so in the end you will have -1 2/5

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In the year 2000, a house was valued at $60 000.

Ne4ueva [31]

The percentage by which the cost is increasing will be 75%.

<h3>What is the percentage?</h3>

The quantity of anything is stated as though it were a fraction of a hundred. A fraction of 100 can be used to express the ratio.

The percentage of the 8th graders who want to go to the water slides is found from;

In the year 2000, a house was valued at $60 000.

In 2010, the same house was valued at $80 000.

The percentage value is found as;

$\% = \frac{60000}{80000} \times 100 \\\\ \% =75 \%$

Hence the percentage by which the cost is increasing will be 75%.

To learn more about percentages, refer to:

brainly.com/question/13450942

#SPJ1

4 0

2 years ago

Val has 2 hours to finish a slide presentation. It takes her 1 ··6 hour to create each slide. Will Val have enough time to creat

Papessa [141]

Answer:

yes

Step-by-step explanation:

10 × 1/6 < 2

4 0

3 years ago

Evaluate the integral of the quantity x divided by the quantity x to the fourth plus sixteen, dx . (2 points) one eighth times t

Anika [276]

Answer:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

Step-by-step explanation:

Given

$\int\limits {\frac{x}{x^4 + 16}} \, dx$

Required

Solve

Let

$u = \frac{x^2}{4}$

Differentiate

$du = 2 * \frac{x^{2-1}}{4}\ dx$

$du = 2 * \frac{x}{4}\ dx$

$du = \frac{x}{2}\ dx$

Make dx the subject

$dx = \frac{2}{x}\ du$

The given integral becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{x}{x^4 + 16}} \, * \frac{2}{x}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{1}{x^4 + 16}} \, * \frac{2}{1}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

Recall that: $u = \frac{x^2}{4}$

Make $x^2$ the subject

$x^2= 4u$

Square both sides

$x^4= (4u)^2$

$x^4= 16u^2$

Substitute $16u^2$ for $x^4$ in $\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16u^2 + 16}} \,\ du$

Simplify

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16}* \frac{1}{8u^2 + 8}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{2}{16}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

In standard integration

$\int\limits {\frac{1}{u^2 + 1}} \,\ du = arctan(u)$

So, the expression becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(u)$

Recall that: $u = \frac{x^2}{4}$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

4 0

3 years ago

If the diameter of an entire coconut is 5 inches, and the coconut meat is 1 inch thick.

Arturiano [62]

Answer:

V=33.51in^3

Step-by-step explanation:

5inch-1 in

=4inch

divide by 2 because the problem gives diameter, not radius. (radius is half of diameter)

The space inside is a sphere so it will be

V=4/3πr^3

V=4/3*pi*(2)^3

V=33.51 inch cubed

6 0

3 years ago

Evaluate (1/3)(m) - 1 - (1/2)(n) m=21 and n=12

Aneli [31]

Answer:

the answer is 0

Step-by-step explanation:

(1/3)(21)-1-(1/2)(12)

The first thing you do is that you multiply 1/3 times 21/1 which equal 7 then you multiply 1/2 times 12/1 which that equal 6 then you solve 7-1-6 and you get 6-6 which equal 0 i hope this help you and i hope you have a goood day.

8 0

3 years ago