Q.2. How does the valency of elements vary in going down a group of the periodic table?
1 answer:
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Answer : The mass of of water present in the jar is, 298.79 g
Solution : Given,
Mass of barium nitrate = 27 g
The solubility of barium nitrate at is 9.02 gram per 100 ml of water.
As, 9.02 gram of barium nitrate present in 100 ml of water
So, 27 gram of barium nitrate present in of water
The volume of water is 299.33 ml.
As we know that the density of water at is 0.9982 g/ml
Now we have to calculate the mass of water.
Therefore, the mass of of water present in the jar is, 298.79 g
Answer : The correct option is, (b) 0.087
Explanation :
The formula used for relative saturation is:
where,
= partial pressure of ethyl acetate
= vapor pressure of ethyl acetate
Given:
Relative saturation = 50 % = 0.5
Vapor pressure of ethyl acetate = 16 kPa
Now put all the given values in the above formula, we get:
Now we have to calculate the molar saturation.
The formula used for molar saturation is:
and,
P(vapor free) = Total pressure - Vapor pressure
P(vapor) = = 8 kPa
So,
P(vapor free) = 100 kPa - 8 kPa = 92 kPa
The molar saturation will be:
Therefore, the molar saturation is 0.087