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Novay_Z [31]
2 years ago
15

How many sodium atoms are in the formula for sodium phosphide

Chemistry
1 answer:
ludmilkaskok [199]2 years ago
6 0

Sodium Phosphide has a formula of Na3P . In order to bond ionically the charges must be equal and opposite. It will take one -3 phosphide ion to balance three +1 sodium ions forming a magnesium phosphide molecule of Na3P

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Use the periodic table to identify each of the following bonds as polar or nonpolar.
Molodets [167]

Answer:

Polar  

Step-by-step explanation:

Electronegativity increases from <em>left to right</em> in the Periodic Table.

Cl is further right than C (both tinted pink) in the portion of the Periodic Table below.

Cl is <em>more electronegative</em> than C, so the Cl has a partial negative charge and the C has a partial positive charge.

The C-Cl bond is polar.

5 0
3 years ago
The equation for the formation of water from hydrogen gas and oxygen gas is 2H2+O2→2H2O.
inn [45]

Answer:

180g

Explanation:

H:1   O:16

2H2+O2 → 2H2O

 2   2(16)       2(1)+(16)

        32              18

Now,

       32g of O → 2(18)g of H2O

       160g of O → 2(18)g divides by 32g times 160g

                            =180g

5 0
2 years ago
Common properties of sodium , calcium , iron ,and gold
Fittoniya [83]
Sodium, calcium, iron and gold are all metals. They all form metallic bonds, in the form of a shared electron cloud. They all have the electrical conductivity and metallic luster which comes with metallic bonds.
7 0
3 years ago
a metal object has a mass of 9.0g and a volume of 1.5ml. what is the density of the object? density= mass/volume​
weeeeeb [17]

The density of the metal object=6.0\frac{g}{m l}

Given:

Volume of the metal object=1.5ml

Mass of the metal object=9.0g

To find:

Density of the metal object

<u>Step by Step Explanation: </u>

Solution:

According to the formula, Density of the metal object can be calculated as

\rho=\frac{m}{v}

Where, m=mass of the metal object

\rho =density of the metal object

v=volume of the metal object

We know the values of v=1.5ml and m=9.0g

Substitute these values in the above equation we get

\rho=\frac{m}{v}

\rho=9.0/1.5

=6.0\frac{g}{m l}

Result:

Thus the density of the metal object is 6.0\frac{g}{m l}

4 0
3 years ago
2.5 * 10^4 gallons to mL
Gre4nikov [31]
(2.5)(10000)=25000

25000 * 3785

ML = 94635294.6 milliliters
6 0
3 years ago
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