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3 years ago

Please help I'm not good at science

Chemistry

1 answer:

Citrus2011 [14]3 years ago

8 0

Answer:

i'm not able to see images but if you type it all i can answer:)

Explanation:

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Calculate the number of mol of S by 1.81

rodikova [14]

It’s 6.022x10^23. This is how many atoms of any element are in one mole of that element. No matter what it is, there are always 6.022x10^23 atoms per mole. So divide 1.81x10^24 by 6.022x10^23 to get approximately 3 moles of sulfur.

5 0

3 years ago

Material A has a small latent heat of fusion. Material B has a large heat of fusion. Which of the following statements is true?

Olin [163]

The correct answer would be the first option. Material A having a smaller latent heat of fusion would mean that it will take only less energy to phase change into the liquid phase. Latent of heat of fusion is the amount of energy needed of a substance to phase change from solid to liquid or liquid to solid.

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3 years ago

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A meteor falls toward Earth's surface. Given that the acceleration due to

ICE Princess25 [194]

Answer:

E = 147000 J

Explanation:

Given that,

The mass of meteor, m = 50 kg

The altitude of the meteor, h = 300 m

We need to find the potential energy of the meteor. The formula for the potential energy is given by :

$E=mgh$

Put all the values,

$E=50\times 9.8\times 300\\\\E=147000\ J$

So, the required potential energy is equal to 147000 J.

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3 years ago

What is the difference between mass number and atomic number

krok68 [10]

Mass number is the number of protons and neutrons in an atom.
Atomic mass is the average mass of all the isotopes of a certain type.

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3 years ago

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Under the right conditions aluminum will react with chlorine to produce aluminum chloride.

salantis [7]

Answer:

$m_{Al}=9.42gAl$

Explanation:

Hello there!

In this case, according to the given chemical reaction:

2 Al + 3 Cl2 --> 2 AlCl3

Whereas there is a 2:3 mole ratio of aluminum to chlorine; it will be possible for us to calculate the required grams of aluminum by using the equality 22.4 L = 1 mol, the aforementioned mole ratio and the atomic mass of aluminum (27.0 g/mol) to obtain:

$m_{Al}=11.727LCl_2*\frac{1molCl_2}{22.4LCl_2}*\frac{2molAl}{3molCl_2} *\frac{27.0gAl}{1molAl} \\\\m_{Al}=9.42gAl$

Regards!

8 0

3 years ago

Please help I'm not good at science​

Please help I'm not good at science