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2 years ago

What is a term called that has no variable? constant or coefficient

Mathematics

2 answers:

tatyana61 [14]2 years ago

8 0

Answer: It is constant

NikAS [45]2 years ago

7 0

Answer:

Constant.

Step-by-step explanation:

Constants are any number that does not have a variable such as x or y, so if they do not have variables, there definitely would not have coefficients. Examples of constants are 2, 5 and 67.

Coefficients are like the 2 in 2x, the 5 in 5y and the 67 in 67xy. All of these numbers have a variable.

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Solve l-20l - l7l PLEASE HELPP IM ON A TEST

tiny-mole [99]

Answer:

Step-by-step explanation:

|-20| = 20 (anything with | | is absolute value, which is always positive), |7| = 7, 20 - 7 = 13.

quick tip: when you see something like -|#|, that would be negative, but if you saw |-#|, it would be positive.

hope it helps lol

7 0

2 years ago

There are three different hoses used to fill a pool: hose x, hose y, and hose z. Hose x can fill the pool in a days, hose y in b

WARRIOR [948]

Answer:

C) I and III only

Step-by-step explanation:

Let full pool is denoted by O

Days Hose x takes to fill pool O = a

Pool filled in one day x = O/a

Days Hose y takes to fill pool O = b

Pool filled in one day y = O/b

Days Hose z takes to fill pool O = c

Pool filled in one day z = O/c

It is given that

a>b>c

$a>b>c>d\\\implies x$

Days if if x+y+z fill the pool together = d

1 day if x+y+z fill the pool together $=O(\frac{1}{a}+\frac{1}{b}+\frac{1}{c})=\frac{O}{d}---(1)$

I) d < c

d are days when hose x, y, z are used together where as c are days when only z is used so number of days when three hoses are used together must be less than c when only z hose is used. So d < c

III) $\frac{c}{3}$

Using (1)

$\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad(a>b>c)\\(ab+bc+ca)\frac{abc}{3ab}\\\\d>\frac{c}{3}$

Similarly

$\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad a>b>c\\(ab+bc+ca)>3bc\\\\d=\frac{abc}{ab+bc+ca}$

So,

$\frac{c}{3}$

3 0

2 years ago

Advanced Order of

Elina [12.6K]

Answer:

113385908

Step-by-step explanation:

use:

Brackets

Indices

Division

Multiplication

Addition

Subtraction

[(66+11)2-6]×766 121

First Brackets

66+11=77

[(77)2-6]×766121

Multiplication:

77×2=154

[154-6]×766121

Subtraction:

154-6=148

Multiplication:

148×766121= 113385908

8 0

2 years ago

Solve.

allsm [11]

The answer is B because when you divide the negative the sign changes :)

6 0

2 years ago

What's the ratio 6kg : 150g

sergeinik [125]

6000:150 or 40:1 Divided both digits by 150

3 0

3 years ago