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2 years ago

6

A parking space shaped like a parallelogram has a base of 17 feet and a height of 9 feet. a car parked in the space is 16 feet l

ong and 6 feet wide. How much of the parking space is not covered by the car?

2 answers:

Sauron [17]2 years ago

6 0

Answer:

37.25% of the parking space isn't covered by the car

Step-by-step explanation:

the car takes up 62.75% of the parking space.

Nesterboy [21]2 years ago

3 0

Answer:

Step-by-step explanation:

area= (17x9)-(16x6)

area=153-96

area=57

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Find the slope line (-2 -1) and (-4 -7)

Alenkinab [10]

Answer:

$m=3$

Step-by-step explanation:

Slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

Here

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2 years ago

Find the obtuse angle between the following pair of straight lines.

ioda

Given:

$y=-2$

$y=\sqrt{3}x-1$

To find:

The obtuse angle between the given pair of straight lines.

Solution:

The slope intercept form of a line is

$y=mx+b$ ...(i)

where, m is slope and b is y-intercept.

The given equations are

$y=0x-2$

$y=\sqrt{3}x-1$

On comparing these equations with (i), we get

$m_1=0$

$m_2=\sqrt{3}$

Angle between two lines whose slopes are $m_1\text{ and }m_2$ is

$\tan \theta=\left|\dfrac{m_2-m_1}{1+m_1m_2}\right|$

Putting $m_1=0$ and $m_2=\sqrt{3}$ , we get

$\tan \theta=\left|\dfrac{\sqrt{3}-0}{1+(0)(\sqrt{3})}\right|$

$\tan \theta=\left|\dfrac{\sqrt{3}}{1+0}\right|$

$\tan \theta=\pm \sqrt{3}$

Now,

$\tan \theta= \sqrt{3}$ and $\tan \theta=-\sqrt{3}$

$\tan \theta= \tan 60^\circ$ and $\tan \theta=\tan (180^\circ-60^\circ)$

$\theta= 60^\circ$ and $\theta=120^\circ$

$120>90$ , so it is an obtuse angle and $60$ , so it is an acute angle.

Therefore, the obtuse angle between the given pair of straight lines is 120°.

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2 years ago