Question A:
Rewriting the table for f(x):
x -1 0 1
f(x) -7 -1 5
Notice that for every increase of one unit in 'x', there are an increase 6 units on f(x). Hence, the gradient of the slope of f(x) is 6.
g(x) = 5x - 4 ⇒ This function follows the general form of the straight line equation, y = mx + c, where 'm' is the gradient and 'c' is the y-intercept.
Hence, the gradient of the slope of g(x) is 5.
The slope of f(x) is steeper than the slope of g(x).
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Question B:
The y-intercept is the value of y where a straight line crosses the y-axis (or when x is zero).
From the table of f(x), the y-intercept is -1 (this is the value of 'y' when 'x' is zero)
From the given function g(x) = 5x - 4, the y-intercept is -4.
f(x) has a greater y-intercept.
Answer:
p=59.19°
Step-by-step explanation:
We first find the length BD
BD=√(6²+5²)=√61
Using Pythagorean theorem,we find p by:
cos(p°)=4/√61
p=cos^-1(4/√61)
p=59.19°
Answer:
Step-by-step explanation:
a = 20(hypotenuse)
b = 12(leg)
z = ?
z= 
= 16
If Gary lost 17 pounds and gained 8 pound back, then we have
-17 pounds + 8 pounds = -9 pounds.
Therefore the additive inverse of the change in Gary's weight is 9 pounds.
That is, Gary lost 9 pounds of weight.
x³ + 2x² - x - 2 < 0
x³ - x + 2x² - 2 < 0
x(x² - 1) - 2(x² - 1) < 0
(x - 2)(x² - 1) < 0
(x - 2)(x - 1)(x + 1) < 0
by chacking we get the solution
x ∈ (-∞,-1) ∪ (-1,1)
