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abruzzese [7]
3 years ago
12

Solve for a-7=-ax-16​

Mathematics
1 answer:
Rudik [331]3 years ago
3 0

Answer:

x=-9/a and a=-9/x

Step-by-step explanation:

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Solve the following systems of equations.<br> y = -x2+2x+1<br> y = 2x+1
boyakko [2]

Answer:

I think it's (0,1) x=0, y=1

Sorry if that's wrong

7 0
3 years ago
Red has already lost three iphones.He didn't spend a lot of money on his newest cellphone because he knows he will eventually lo
iVinArrow [24]

Answer:

deductive reasoning

Step-by-step explanation:

8 0
3 years ago
Subtract the fractions and simplify the answer 7 8/9-5 3/5
weeeeeb [17]
One way in which to do this problem would involve subtracting 5 from 7 (result:  2) and then subtracting 3/5 from 8/9.
To subtract 3/5 from 8/9, you'd need to find the lowest common denominator (LCD) of 3/5 and 8/9, convert both fractions to have this LCD, and then subtract.

The LCD is (5)(9)=45.  Then 8/9 and 3/5 become 40/45 and 27/45.

Subtracting 27/45 from 40/45 results in the fraction 13/45.
Then the full solution is  2 13/45.

You could also do this problem by converting  7 8/9    and   5 3/5 into improper fractions:

71/9 - 28/5.  Again, the LCD is 45.  Can you rewrite both fractions with 45 as the common denominator and then perform the subtraction?
4 0
4 years ago
The center of a hyperbola is (−4,3) , and one vertex is (−4,7) . The slope of one of the asymptotes is 2.
Monica [59]

Answer:

The answer to your question is below

Step-by-step explanation:

C (-4, 3)

V (-4, 7)

asymptotes = 2 = \frac{b}{a}

- This is a vertical hyperbola, the equation is

       \frac{(y - k)^{2} }{a^{2} } + \frac{(x - h)^{2} }{b^{2} } = 1

slope = 2

a is the distance from the center to the vertex = 4

b = 2(4) = 8

       \frac{(y - 3)^{2} }{4^{2} } + \frac{(x + 4)^{2} }{8^{2} } = 1

       \frac{(y - 3)^{2} }{16} + \frac{(x + 4)^{2} }{64} = 1

7 0
3 years ago
Read 2 more answers
Can the numbers 24, 32, 42, be the lengths of the three sides of the right triangle? Explain why or why not
Musya8 [376]
No the don't add up to one eighty I'm pretty sure if not tell me
8 0
3 years ago
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