On what evidence do you accept the statement,"Aboslute zero is at -273."

A jet accelerates at a=3.92 m/s2 from rest until it reaches its takeoff velocity of 360 km/hr. It has to travel for 5 seconds at

Art [367]

Answer:

$\Delta s = 1775.510\,m$

Explanation:

The minimum distance for takeoff is:

$\Delta s = \Delta s_{1} + \Delta s_{2}$

$\Delta s = \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot a} + v_{f}\cdot \Delta t$

$\Delta s = \frac{(100\,\frac{m}{s} )^{2}-(0\,\frac{m}{s} )^{2}}{2\cdot (3.92\,\frac{m}{s^{2}})}+(100\,\frac{m}{s} )\cdot (5\,s)$

$\Delta s = 1775.510\,m$

7 0

3 years ago

1

Keith_Richards [23]

Yeah I conclude that the answer is A because it need distance but with out charge it would no get that distance so yeah A

5 0

2 years ago

A submerged submarine alters its _____ to rise or fall in the water.

Dima020 [189]

Are there any answer choices?
Submarines use <span>buoyancy by filling ballast tanks up with water. When they are filled with water, they are more dense than the surrounding water, so they are able to sink. If they want to rise, they fill these tanks up with air so that the density is less than the water it surrounds.
Hope this helps! :)</span>

3 0

4 years ago

Read 2 more answers

A water trough is 12 feet long, and its cross section is an equilateral triangle with sides 2 feet long. Water is pumped into th

MAXImum [283]

Answer:

The water level rises at 11.76 $ft^{2} /s$

$h=\sqrt{3/2} s$ let be h: height and s: side of an equilateral triangle

Explanation:

The picture shows a diagram of the situation, first we have to determine the height of the trough as follows:

With the Pytagorean Theorem we can find out that:

$h^{2} =s^{2} -s^{2} /4 =\sqrt{3} /2 s$

Then, the area of an equilateral triangle, as any triangle, is a half of its base times its height:

$A=\frac{1}{2} hs=\frac{1}{2} \frac{\sqrt{3} }{2} s^{2} =\frac{\sqrt{3} }{4} s^{2}$

Replacing values, we have:

$A=1.73ft^{2}$

That is the total area of the trough, but the problem specifies that it has been filled until 0.5 ft. Therefore, we have to find the cross section area of the water flow by substracting the total area minus the unfilled area of the trough:

$h_{u}: height of the unfilled triangle\\s_{u} : side of the unfilled triangle\\A_{u}: area of the unfilled triangle\\h_{u}=\sqrt{3} -0.5 =1.23\\s_{u}= \frac{2}{\sqrt{3} } 1.23=1.42\\A_{u}=\frac{\sqrt{3} }{4} 1.42^{2} =0.87ft^{2} A_{u}$

Then, the cross section area of water flow is

$A_{s} =1.73ft^{2} -0.87ft^{2} =0.85ft^{2}$

Finally, to determine the speed of water flow at this point we solve for v, the flow formula:

$Q: water flow\\v: speed\\Q=vA\\v=Q/A =\frac{10ft^{3}/s }{0.85ft^{2} } =11.76 \frac{ft^{2}}{s}$

6 0

3 years ago

What is the SI unit of drift velocity

Andrej [43]

SI or the Systeme' Internationale' is a body in science that fixes the unit of measurements used for different basic dimensions. The SI unit for distance is meter while that of time is second. Since velocity is equal to distance over time, the SI unit for velocity is m/s.

8 0

3 years ago

On what evidence do you accept the statement,"Aboslute zero is at -273."​

On what evidence do you accept the statement,"Aboslute zero is at -273."