The density of the metal object=6.0
Given:
Volume of the metal object=1.5ml
Mass of the metal object=9.0g
To find:
Density of the metal object
<u>Step by Step Explanation:
</u>
Solution:
According to the formula, Density of the metal object can be calculated as

Where, m=mass of the metal object
=density of the metal object
v=volume of the metal object
We know the values of v=1.5ml and m=9.0g
Substitute these values in the above equation we get

=9.0/1.5
=6.0
Result:
Thus the density of the metal object is 6.0
Answer: The hydroxide concentration of this sample is 
Explanation:
When an expression is formed by taking the product of concentration of ions raised to the power of their stoichiometric coefficients in the solution of a salt is known as ionic product.
The ionic product for water is written as:
![K_w=[H^+]\times [OH^-]](https://tex.z-dn.net/?f=K_w%3D%5BH%5E%2B%5D%5Ctimes%20%5BOH%5E-%5D)
![7.7\times 10^{-14}=[H^+]\times [OH^-]](https://tex.z-dn.net/?f=7.7%5Ctimes%2010%5E%7B-14%7D%3D%5BH%5E%2B%5D%5Ctimes%20%5BOH%5E-%5D)
As ![[H^+]=[OH^-]](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D%5BOH%5E-%5D)
![2[OH^-]=7.7\times 10^{-14}](https://tex.z-dn.net/?f=2%5BOH%5E-%5D%3D7.7%5Ctimes%2010%5E%7B-14%7D)
![[OH^-]=3.85\times 10^{-7}](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D3.85%5Ctimes%2010%5E%7B-7%7D)
Thus hydroxide concentration of this sample is 
Answer:
The 99.68% of the aspirin is present in the neutral form
Explanation:
Aspirin, Acetylsalicylic acid, is a weak acid with pKa = 3.5
Using Henderson-Hasselbalch equation:
pH = pKa + log [A⁻] / [HA]
<em>Where [A⁻] is the ionized form and HA the neutral form of the acid</em>
<em />
Replacing with a pH of stomach of 1.0:
1.0 = 3.5 + log [A⁻] / [HA]
-2.5 = log [A⁻] / [HA]
3.16x10⁻³ = [A⁻] / [HA] <em>(1)</em>
<em />
A 100% of aspirin is = [A⁻] + [HA]
100 = [A⁻] + [HA] <em>(2)</em>
<em></em>
Replacing (2) in (1)
3.16x10⁻³ = 100 - [HA] / [HA]
3.16x10⁻³[HA] = 100 - [HA]
1.00316 [HA] = 100
[HA] = 99.68%
<h3>The 99.68% of the aspirin is present in the neutral form</h3>
Answer:
With regards to the final composition of the mixture in the vessel at equilibrium, there will be very little amount of the reactants (BrOCl and BrCl), since some amounts of each have been used to form the products (Br2 and OCl).
Answer:
6
Explanation:
This can be calculated from a general equation from the which the energies of the various spectral lines of hydrogen shown in the image attached. The various series of hydrogen are:
Lyman, Balmer, Paschen,Bracket and Pfund series.