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3 years ago

What two subatomic particles have to be different in order to have an ion?

Chemistry

1 answer:

lisabon 2012 [21]3 years ago

6 0

Answer:

A)Protons and electrons

Explanation:

An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.

All these three subatomic particles construct an atom. A neutral atom have equal number of proton and electron. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons. The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom.

when an atom lose or gain the electron ions are formed and number of protons and electrons no longer remain the same.

For example:

An atom of sodium when lose one electron it form positive ion. The number of electrons became 10 and number of protons remain 11.

Na → Na⁺ + 1e⁻

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Na: 1s22sC2pP3s C= D= E=

KengaRu [80]

Answer

1s22s22p63s1

Explanation:

5 0

3 years ago

A sample of calcium carbonate weighs 2.1 kilograms (kg). There are 1,000 grams (g) in 1 kg, and 1 Times. 109 nanograms (ng) in 1

TiliK225 [7]

Answer:

2.1 x 10¹²ng

Explanation:

Mass of the calcium carbonate given is:

2.1kg

We need to take this mass to nanogram, ng.

Since :

1000g = 1kg

10⁹g = 1ng

So;

1kg = 1000 x 10⁹ = 10¹²ng

So;

2.1kg will give;

Since

1kg gives 10¹²ng

2.1kg will give 2.1 x 10¹²ng

5 0

3 years ago

_ is the process in which an element spontaneously transforms into another isotope of the same element, or into a different elem

MariettaO [177]

Answer:

Nuclear transmutation

Explanation:

The process in which an element spontaneously transforms into another isotope of the same element, or into a different element is called nuclear transumutation. It occurs when the number of protons or neutrons in the nucleus of an atom is changed.

8 0

3 years ago

If you dilute 18.8 mL of a 3.5 M solution to make 296.6 mL of solution, what is the molarity of the dilute solution?

hodyreva [135]

Answer:

0.22M

Explanation:

We will be using the law of dilutions. We are simply increasing the amount of solvent to create a larger volume of solution.

So: moles before dilution = moles after dilution & $moles_{concentrated} = moles_{dilute}$ . And M = moles/liter of solution, so if we express this as moles = M x $L_{soln}$ .

That is how we derive the formula we will be using: $M_{concentrated} * Vol_{conc} = M_{dilute} * Vol_{dilute}$

$M_{1} * Vol_{1} = M_{2} * Vol_{2}$

Applying this formula to our problem, we can substitute the variables with the given values to find the molarity of the dilute solution.

M1 = 3.5M

V1 = 18.8mL

M2 = ?

V2 = 296.6mL

Equation: (3.5M)(18.8mL) = (296.6mL)(M2)

==> 65.8M*mL = 296.6mL * M2

==> M2 = (65.8 M*mL)/296.6mL

==> M2 = 0.22M

8 0

3 years ago

The density of toluene (C7H8) is 0.867 g/mL, and the density of thiophene (C4H4S) is 1.065 g/mL. A solution is made by dissolvin

nadya68 [22]

Answer:

(a) 0.039

(b) 0.384 M

Explanation:

We have the following data:

d(C₇H₈) = 0.867 g/mL

d(C₄H₄S) = 1.065 g/mL

V(C₇H₈) = 250.0 mL

mass(C₄H₄S) = 8.10 g

(a) The mole fraction of C₄H₄S in the solution is the number of moles of C₄H₄S divided into the total moles of the solution:

X(C₄H₄S) = moles C₄H₄S/ total moles

To calculate the moles, we need the molecular weight (MW) of each compound:

MW(C₄H₄S) = (4 x 12 g/mol) + (4 x 1 g/mol) + 32 g/mol = 84 g/mol

MW(C₇H₈) = (7 x 12 g/mol) + (8 x 1 g/mol) = 92 g/mol

Thus, we calculate the moles of C₄H₄S by dividing the mass into the MW(C₄H₄S):

moles C₄H₄S = mass(C₄H₄S)/MW(C₄H₄S)= 8.10 g/(84 g/mol) = 0.096 moles

Then, we have to calculate the moles of C₇H₈. First, we need the mass, obtained from the product of the density by the volume:

mass(C₇H₈)= d(C₇H₈) x V(C₇H₈) = 0.867 g/mL x 250.0 mL = 216.75 g

Thus, we divide the mass of C₇H₈ into the MW to calculate the moles of C₇H₈:

moles C₇H₈ = mass(C₇H₈)/MW(C₇H₈) = 216.75 g/(92 g/mol) = 2.35 moles

The total moles is obtained from the addition of the moles of the solute (C₄H₄S) and the solvent (C₇H₈):

total moles = moles C₄H₄S + moles C₇H₈ = 0.096 moles + 2.35 moles = 2.45 moles

Finally, we calculate the mole fraction of C₄H₄S:

X(C₄H₄S) = moles C₄H₄S/ total moles = 0.096 moles/2.45 moles = 0.039

(b) The molarity of C₄H₄S is calculated as follows:

M(C₄H₄S) = moles C₄H₄S/1 liter solution

Assuming that the total volume of the solution is the volume of solvent (C₇H₈), we calculate the molarity of C₄H₄S by dividing the moles into the volume of solvent in liters:

V(C₇H₈) = 250.0 mL = 0.250 L

M(C₄H₄S) = 0.096 moles/(0.250 L) = 0.384 mol/M = 0.384 M

(c) Assuming that the volumes of solute and solvent are additive, we can add the volumes of C₄H₄S and C₇H₈. First, we need the volume of C₄H₄S, which can be calculated from the mass and density:

V(C₄H₄S) = mass(C₄H₄S)/ d(C₄H₄S) = 8.10 g/(1.065 g/mL) = 7.606 mL = 0.0076 L

Now, we add the volumes:

total volume = V(C₇H₈) + V(C₄H₄S) = 0.250 L + 0.0076 L = 0.2576 L

Finally, we recalculate the molarity of C₄H₄S:

M(C₄H₄S)= moles C₄H₄S/ total volume = 0.096 moles/0.2576 L = 0.373 M

7 0

3 years ago