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2 years ago

A mixture of 117.9 g of P and 121.8 g of O, reacts completely to form P4O6 and P4O10. Find the masses of P4O6 and P4O10

Chemistry

1 answer:

Alex17521 [72]2 years ago

4 0

Answer:

Mass of P4O6=103.4

P4O10=133.48

Explanation:

Balanced reaction is:

8P +8 $O_{2}$ ⇒ $P_{4} O_{6}$ + $P_{4} O_{10}$

Both reactant completely vanishes as equivalent of bot are equal.

Moles of P= $\frac{117.9}{31}$ =3.80

Moles of $O_{2}$ = $\frac{117.9}{31}$ =3.80

No. of moles of formed product are equal and is $\frac{1}{8}$ th of mole of any of reactant.

Thus weight of $P_{4} O_{6}$ = $\frac{3.80}{8}$ ×220 ≈103.41

weight of $P_{4} O_{10}$ = $\frac{3.80}{8}$ ×284 ≈133.48

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