Question

A mixture of 117.9 g of P and 121.8 g of O, reacts completely to form P4O6 and P4O10. Find the masses of P4O6 and P4O10

Answer 1

Answer:

Mass of P4O6=103.4

            P4O10=133.48

Explanation:

Balanced reaction is:

8P +8$O_{2}$  ⇒$P_{4} O_{6}$ +$P_{4} O_{10}$

Both reactant completely vanishes as equivalent of bot are equal.

Moles of P=$\frac{117.9}{31}$ =3.80

Moles of $O_{2}$ =$\frac{117.9}{31}$ =3.80

No. of moles of formed product are equal and is $\frac{1}{8}$th of mole of any of reactant.

Thus weight of  $P_{4} O_{6}$ =$\frac{3.80}{8}$×220 ≈103.41

        weight of  $P_{4} O_{10}$ =$\frac{3.80}{8}$×284 ≈133.48