1 mole ----------- 6.02 x 10²³ atoms
? mole ---------- 24.08 x 10²³ atoms
moles B = ( 24.08 x 10²³) x 1 / 6.02 x 10²³
moles B = 24.08 x 10²³ / 6.02 x 10²³
= 4 moles
Answer B
hope this helps!
Answer:
oxidation number is correct!! :)
Explanation:
Answer:

Explanation:
The quantity of heat transfered from the jellybean to the water is:



Answer:
How much heat energy required to convert following?
How much heat energy, in kilojoules, is required to convert 47.0 g of ice at -18.0 C to water at 25.0 C ?
Specific Heat of Ice - 2.09 j/g * c
This is how I did it and the answer is wrong...Please check and correct me
Q = m * Cice * Change in Temp
Q = (47.0 g)(2.09 J/g*c)(43) = 4222.6 J * 0.001 kj / j = 4.22 kj
Answer:
c
Explanation:
it could honestly be wrong but I'm not sure