Answer:
Rubidium
Explanation:
Rubidium is an alkali metal that has 37 protons 48 neutrons and 1 valence electron
The element which would have the lowest electronegativity is: an element with a small number of valence electrons and a large atomic radius.
Atomic radii can be defined as a measure of the size (distance) of the atom of a chemical element such as hydrogen, oxygen, carbon, nitrogen etc, typically from the nucleus to the valence electrons. The atomic radius of a chemical element decreases across the periodic table, typically from alkali metals (group one elements such as hydrogen, lithium and sodium) to noble gases (group eight elements such as argon, helium and neon). Also, the atomic radius of a chemical element increases down each group of the periodic table, typically from top to bottom (column).
Generally, atoms with relatively large atomic radii tend to have a low electronegativity, ionization energy and a low electron affinity.
Valence electrons can be defined as the number of electrons present in the outermost shell of an atom. Thus, number of valence electrons is typically used to determine the chemical properties of elements such as electronegativity.
Electronegativity can be defined as the ability or tendency of the atom of an chemical element to attract any shared pair of electrons.
In conclusion, a chemical element that has small number of valence electrons and a large atomic radius would have the lowest electronegativity.
Find more information: brainly.com/question/24370190
F- is the smallest because it accepts 1 electron 2 make its atomic number 10 making it have jst 2 orbitals but O²-,N³- and Na have their atomic number to be 18,17 and 11 respectively with 3 orbitals..
hope this helps *winks*
At the same time there is increased usage of chlorofluorocarbon [CFC].
CFC are halogenated compounds which have ability to destroy the ozone layer. When ultraviolet ray strike CFC in the atmosphere, it breaks the forces holding the molecule together and yield a chlorine atom. The chlorine atom then react with the ozone layer, breaking it apart and destroying it.<span />
Answer:
1.05 L
Explanation:
There is some info missing I think this is the original question.
<em>A laboratory experiment requires 250 millimeters of water boiling. it also requires 100 mills of water for a cooling process. If a student performs the experiment three times, how much total water will the student need? Give your answer in liters.</em>
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Step 1: Calculate the volume required for each experiment.
The volume required is the sum of the volumes used: 250 mL + 100 mL = 350 mL
Step 2: Calculate the volume required for the 3 experiments
We have to multiply the volume required for each experiment by 3.
3 × 350 mL = 1050 mL
Step 3: Convert the volume to liters
We use the relation 1 L = 1000 mL.
1050 mL × (1 L/1000 mL) = 1.05 L
