Answer) D. ketone. Im not sure if its right tho
Answer : The enthalpy of the reaction = -1839.6 KJ
Solution : Given,
= -520.0 KJ/mole
= -1699.8 KJ/mole
The balanced chemical reaction is,

Formula used :


We know that the standard enthalpy of formation of the element is equal to Zero.
Therefore, the enthalpy of formation of (Mn) and (Al) is equal to zero.
Now, put all the values in above formula, we get
![\Delta (H_{f})_{reaction}=[2moles\times (-1699.8 KJ/mole)}+3moles\times (0\text{ KJ/mole}})]-[(3moles\times(-520.0KJ/mole }+4moles\times(0\text{ KJ/mole})]](https://tex.z-dn.net/?f=%5CDelta%20%28H_%7Bf%7D%29_%7Breaction%7D%3D%5B2moles%5Ctimes%20%28-1699.8%20KJ%2Fmole%29%7D%2B3moles%5Ctimes%20%280%5Ctext%7B%20KJ%2Fmole%7D%7D%29%5D-%5B%283moles%5Ctimes%28-520.0KJ%2Fmole%20%7D%2B4moles%5Ctimes%280%5Ctext%7B%20KJ%2Fmole%7D%29%5D)
= (-3399.6) + (1560)
= -1839.6 KJ
Answer: C. Salt and Water
Explanation:
The reaction between an acid and a base will have salt and water as its end product. This process is known " Neutralization Reaction".
HCl + NaOH -----------> NaCl + H2O
Hydrochloric Sodium Sodium Water
Acid Hydroxide (base) Chloride(Salt)
You start by using proportions to find the number of liters of solution:
180 g of glucose / 1 liter of solution = 18 g of glucose / x liter of solution
=> x = 18 g of glucose * 1 liter of solution / 180 g of glucose = 0.1 liter of solution.
If you assume that the 18 grams of glucose does not apport volume to the solution but that the volume of the solution is the same volumen of water added (which is the best assumption you can do given that you do not know the how much the 18 g of glucose affect the volume of the solution) then you should add 0.1 liter of water.
Answer: 0.1 liter of water.
Answer:
The answer to your question is 64.02 g of H₂O
Explanation:
Data
Mass of magnesium sulfate hepta hydrated = 125 g
Mass of water = ?
Process
1.- Calculate the molar mass of the salt and the molar mass of water
molar mass of MgSO₄ 7H₂O = 24 + 32 + 64 + 14 + 112 = 246 g
mass of H₂O = 2 + 16 = 18 g
2.- Use proportions to calculate the mass of water in the epsom salt
246 g MgSO₄ 7H₂O------------------------- 126 g of H₂O
125 g ------------------------- x
x = (125 x 126)/246
x = 15750/246
x = 64.02 g of H₂O