Answer: 1. moles
2. 90 mg
Explanation:
According to stoichiometry:
1 mole of ozone is removed by 2 moles of sodium iodide.
Thus moles of ozone is removed by = moles of sodium iodide.
Thus moles of sodium iodide are needed to remove moles of
2.
According to stoichiometry:
1 mole of ozone is removed by 2 moles of sodium iodide.
Thus 0.0003 moles of ozone is removed by = moles of sodium iodide.
Mass of sodium iodide= (1g=1000mg)
Thus 90 mg of sodium iodide are needed to remove 13.31 mg of .
Hydrocarbons. They usually burn. In fact, I can't think of one that does not.
According to periodic trends, bismuth has the greatest atomic radius.
Answer:
1 Ca(OH)2 + 2 HCl ---> 1 CaCl2 + 2 H2O