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2 years ago

PLEASE HELP! The LCM of 10 and 12 is ___.

Mathematics

1 answer:

slava [35]2 years ago

5 0

Answer:

LCM of 12 and 10= 60

hope this helps <3

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A recent survey showed that in a sample of 100 elementary school teachers, 15 were single. In a sample of 180 high school teache

trapecia [35]

Answer:

By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single

Step-by-step explanation:

let p1 be the proportion of elementary teachers who were single

let p2 be the proportion of high school teachers who were single

Then, the null and alternative hypotheses are:

$H_{0}$ : p2=p1

$H_{a}$ : p2>p1

We need to calculate the test statistic of the sample proportion for elementary teachers who were single.

It can be calculated as follows:

$\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }$ where

p(s) is the sample proportion of high school teachers who were single ( $\frac{36}{180} =0.2$ )
p is the proportion of elementary teachers who were single ( $\frac{15}{100} =0.15$ )

N is the sample size (180)

Using the numbers, we get

$\frac{0.2-0.15}{\sqrt{\frac{0.15*0.85}{180} } }$ ≈ 1.88

Using z-table, corresponding P-Value is ≈0.03

Since 0.03>0.01 we fail to reject the null hypothesis. (The result is not significant at α = 0.01)

8 0

3 years ago

Please make a graph using the information below

Bogdan [553]

Answer:

ikoookokokokolokokokokokokokok

7 0

3 years ago

Can anyone give me the answer and tell me how you did it?

pav-90 [236]

Answer:

the answer is 150

Step-by-step explanation:

8 0

3 years ago

Suppose the number of radios in a household has a binomial distribution with parameters n=11 and p=40%. Find the probability of

Ivenika [448]

Answer:

Step-by-step explanation:

The formula for binomial distribution is expressed as

P(x=r) = nCr × q^(n-r) × p^r

From the information given,

n = 11

p = 40% = 40/100 = 0.4

q = 1 - 0.4 = 0.6

x represent the number of radios

a) P( x = 1) or P(x = 9)

P(x = 1) = 11C1 × 0.6^(11-1) × 0.4^1

P(x = 1) = 0.027

P(x = 9) = 11C9 × 0.6^(11-9) × 0.4^9

P(x = 9) = 0.0052

P( x = 1) or P(x = 9) = 0.027 + 0.0052 = 0.0322

b) P(x lesser than or equal to 7) = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4) + P(x = 5) + P(x = 6)

P(x = 0) = 11C0 × 0.6^(11-0) × 0.4^0 = 0.004

P(x = 1) = 0.027

P(x = 2) = 11C2 × 0.6^(11-2) × 0.4^2 = 0.089

P(x = 3) = 11C3 × 0.6^(11-3) × 0.4^3 = 0.177

P(x = 4) = 11C4 × 0.6^(11-4) × 0.4^4 = 0.24

P(x = 5) = 11C5 × 0.6^(11-5) × 0.4^5 = 0.22

P(x = 6) = 11C6 × 0.6^(11-6) × 0.4^6 = 0.15

P(x = 7) = 11C7 × 0.6^(11-7) × 0.4^7 = 0.15

P(x lesser than or equal to 7) = 0.004 + 0.027 + 0.089 + 0.177 + 0.24 + 0.22 + 0.15 + 0.07 = 0.977

c) P(x greater than or equal to 5) = 1 - P(x lesser than or equal to 4) = 1 - (0.004 + 0.027 + 0.089 + 0.177 + 0.24) = 1 - 0.537 = 0.463

d) P(x lesser than 9) = P(x lesser than or equal to 7) + P(x = 8)

P(x = 8) = 11C8 × 0.6^(11-8) × 0.4^8 = 0.02

P(x lesser than 9) = 0.977 + 0.02 = 0.997

e. P(x greater than 7) = 1 - P(x lesser than or equal to 7) = 1 - 0.977 = 0.023

5 0

3 years ago

Which order pair is a solution of this equation. 5x+y=-25

crimeas [40]

Answer:

(-5,0) or (0,-25) is another solution

Step-by-step explanation:

Do you have a list of choices? If not, you could choose random choices for x and y to determine if they are solutions. Start by letting y = 0. We see that x = -5, so (-5, 0) is a solution to this equation. In fact, it represents the x-intercept of this line. Now, let x = 0. We now see that y = -25, so (0, -25) is another solution to the equation of this line. This coordinate pair is the y-intercept of the line. Try using other values of x and y to see if you can come up with other solutions to this equation.

7 0

3 years ago

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