Answer:
Acceleration of the meteorite, 
Explanation:
It is given that,
A Meteorite after striking struck a car, v = 0
Initial speed of the Meteorite, u = 130 m/s
Distance covered by Meteorite, s = 22 cm = 0.22 m
We need to find the magnitude of its deceleration. It can be calculated using the third equation of motion as :
So, the deceleration of the Meteorite is 
. Hence, this is the required solution.
Answer:
acceleration = v-u /t
30- 20/5
= 10/5 = 2m/sec²
Force = mass * acceleration
Force = 0.1 * 2
Force = 0.2 Newton
It would need to be over 20 because if the load of the Pulley E is 20 and the effort is 20, then they will be equal and the Pulley would not move, so your answer is at least 20
Answer:
Explanation:
<u>Dynamics</u>
When a particle of mass m is subject to a net force F, it moves at an acceleration given by
The particle has a mass of m=2.37 Kg and the force is horizontal with a variable magnitude given by
The variable acceleration is calculated by:
The instant velocity is the integral of the acceleration:
Integrating
