We will use two definitions to solve this problem. The first will be given by the conservation of energy, whereby the change in kinetic energy must be equivalent to work. At the same time, work can be defined as the product between the force by the distance traveled. By matching these two expressions and clearing for the Force we can find the desired variable.
Thus the force acting on the sled is,
Replacing,
Therefore the Force acting on the sled is 32N
Answer:
yes
Explanation:
By definition, the speed of an object is the rate of change of its position.Velocity, on the other hand, is the measurement of the rate and direction of change in the position of an object. Since it is a vector physical quantity, both magnitude and direction are required to define it
Answer:
The mass of the heaviest box you will be able to move with this applied force = 61.4 kg
Explanation:
From the diagram attached, the forces acting on the box include the weight of the box, applied force on the box, normal reaction of the surface on the box and the Frictional force in the opposite direction to the applied force.
For the box to be able to move, the applied force must have a horizontal component that at least matches the Frictional force between the box and the surface. This is the force balance in the horizontal direction.
Resolving the applied force into horizontal and vertical components,
Fₓ = 750 cos 25° = 679.73 N
Fᵧ = 750 sin 25° = 316.96 N
Doing a force balance in the vertical axis,
N = (mg + 316.96)
Frictional force = μN = μ (mg + 316.96)
μ = 0.74, g = 9.8 m/s²
Frictional force = Fᵧ
μ (mg + 316.96) = 679.73
0.74(9.8m + 316.96) = 679.73
7.252m + 234.5504 = 679.73
7.252m = 679.73 - 234.5504 = 445.1796
m = (445.1796/7.252)
m = 61.4 kg
Hope this Helps!!!
Well, they both start chain reactions and they are also both used in certain nuclear bombs. Also they are both natural processes that occur in the sun, where hydrogen fuses with helium atoms and then they split by the process of fission.
Answer:
0.3 N
Explanation:
i = 400 A
B = 30 x 10^-6 T
L = 25 m
Force due the current carrying conductor placed in a magnetic field
F = B i L SinФ
where, Ф be the angle between length vector and magnetic field vector
F = 30 x 10^-6 x 400 x 25 = 0.3 N