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mars1129 [50]
2 years ago
8

A roller coaster uses 800 000 J of energy to get to the top of the first hill. During this climb, it gains 500 000 J of potentia

l energy and pauses (velocity = 0) for a fraction of a second at the very top before heading down the other side.
a) Draw a sankey diagram for a roller coaster's climb.
Physics
1 answer:
Zarrin [17]2 years ago
6 0

Answer:

<em>Good Luck!</em>

Explanation:

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Which sound wave-object interaction is used by animals in echolocation?
tekilochka [14]
The answer is reflection
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3 years ago
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Neutron stars, such as the one at the center of the Crab Nebula, have about the same mass as our sun but have a much smaller dia
Crank

Answer:

Wn = 9.14 x 10¹⁷ N

Explanation:

First we need to find our mass. For this purpose we use the following formula:

W = mg

m = W/g

where,

W = Weight = 675 N

g = Acceleration due to gravity on Surface of Earth = 9.8 m/s²

m = Mass = ?

Therefore,

m = (675 N)/(9.8 m/s²)

m = 68.88 kg

Now, we need to find the value of acceleration due to gravity on the surface of Neutron Star. For this purpose we use the following formula:

gn = (G)(Mn)/(Rn)²

where,

gn = acceleration due to gravity on surface of neutron star = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

Mn = Mass of Neutron Star = Mass of Sun = 1.99 x 10³⁰ kg

Rn = Radius of neutron Star = 20 km/2 = 10 km = 10000 m

Therefore,

gn = (6.67 x 10⁻¹¹ N.m²/kg²)(1.99 x 10³⁰ kg)/(10000)

gn = 13.27 x 10¹⁵ m/s²

Now, my weight on neutron star will be:

Wn = m(gn)

Wn = (68.88)(13.27 x 10¹⁵ m/s²)

<u>Wn = 9.14 x 10¹⁷ N</u>

3 0
3 years ago
What is the resultant of a pair of one pound forces at right angles to each other?
OleMash [197]

Answer:

F_R=\sqrt{2} \ pound.force

Explanation:

Given that there are two force of 1 pound each at right angles to each other.

The from the vector law of addition:

F_R=\sqrt{F_1^2+F_2^2}

where:

F_R= resultant force

F_1\ \&\ F_2 be the two of the forces to be added.

F_R=\sqrt{1^2+1^2}

F_R=\sqrt{2} \ pound.force

8 0
3 years ago
DESPERATE WILL GIVE BRAINLSIT AND THANKS
Eva8 [605]

Hello!

My best guess would be hydrogen and oxygen.

hopefully this helps!

8 0
3 years ago
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A quarter is flipped from a height of 1.45 m above the ground. How much time will it take to reach the ground if the person flip
Artemon [7]

It will take the quarter 0.151 seconds to reach the ground.

<u>Given the following data:</u>

  • Height = 1.45 meters
  • Initial velocity = 10.32 m/s

We know that acceleration due to gravity (a) for an object is equal to 9.8 meter per seconds square.

To find how much time it will take the quarter to reach the ground, we  would use the second equation of motion.

Mathematically, the second equation of motion is given by the formula;

S = ut + \frac{1}{2} at^2

Where:

  • S is the height or distance covered.
  • u is the initial velocity.
  • a is the acceleration.
  • t is the time measured in seconds.

Substituting the values into the formula, we have;

1.45 = 10.32(t) + \frac{1}{2} (9.8)t^2\\\\1.45 = 10.32t + 4.9t^2\\\\4.9t^2 + 10.32t - 1.45 = 0

The standard form of a quadratic equation is:

ax^2 + bx + c = 0

a = 4.9, b = 10.32 and c = 1.45

We would solve the above quadratic equation by using the quadratic equation formula;

x = \frac{-b\; \pm \;\sqrt{b^2 - 4ac}}{2a}

Substituting the values, we have;

t = \frac{-10.32\; \pm \;\sqrt{10.32^2\; - \;4(4.9)(1.45)}}{2(4.9)}\\\\t = \frac{-10.32\; \pm \;\sqrt{106.5024\; - \;28.42}}{9.8}\\\\t = \frac{-10.32\; \pm \;\sqrt{78.0824}}{9.8}\\\\t = \frac{-10.32\; \pm \;8.84}{9.8}\\\\t = \frac{-10.32\; + \;8.84}{9.8}\\\\t = \frac{1.48}{9.8}

<em>Time, t = 0.151 seconds.</em>

Therefore, it will take the quarter 0.151 seconds to reach the ground.

Read more: brainly.com/question/8898885

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2 years ago
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