Answer:
128379.69 J
Explanation:
Potential energy: This can be defined as the energy of a body to to position in the gravitational field. The S.I unit of potential energy is Joules (J).
The expression for potential energy is given as,
ΔEp = mgΔH
ΔEp = mg(H₂-H₁)..................... Equation 1
Where ΔEp =change in Potential Energy, m = mass of the man, g = acceleration due to gravity, H₂ = Height of the 37th floor, H₁ = height of the first floor
Given:m = 91.2 kg, g = 9.8 m/s², H₁ = 3.99 m, H₂ = 3.99×37 = 147.63 m.
Substitute into equation 1
ΔEp = 91.2(9.8)(147.63-3.99)
ΔEp = 893.76(143.64)
ΔEp = 128379.69 J.
Answer:
A) determine magnetic fields
For 0 ≤ r ≤ a
Magnetic field = ∅ 
For a ≤ r ≤ b
Magnetic field = ∅ 
For b ≤ r ≤ c
Magnetic field in the region = ∅ ![\frac{I}{2\pi r} [ c^2 - r^2 / c^2-b^2 ]](https://tex.z-dn.net/?f=%5Cfrac%7BI%7D%7B2%5Cpi%20r%7D%20%5B%20c%5E2%20-%20r%5E2%20%2F%20c%5E2-b%5E2%20%5D)
For r ≥ c
magnetic filed in the region = 0
B ) attached below
Explanation:
<u>A) Determine the magnetic field in the following regions</u>
i) For 0 ≤ r ≤ a
Magnetic field = ∅ 
attached below is the detailed solution
ii) For a ≤ r ≤ b
Magnetic field = ∅ 
attached below is the detailed solution
iii) For b ≤ r ≤ c
Magnetic field in the region = ∅ ![\frac{I}{2\pi r} [ c^2 - r^2 / c^2-b^2 ]](https://tex.z-dn.net/?f=%5Cfrac%7BI%7D%7B2%5Cpi%20r%7D%20%5B%20c%5E2%20-%20r%5E2%20%2F%20c%5E2-b%5E2%20%5D)
attached below is the detailed solution
iv) For r ≥ c
magnetic filed in the region = 0 and this is because the net current enclosed in the region = 0
The complete cycle of Moon phases takes 29.53 days.
The "First Quarter" has that name because it's one quarter of the time
from one New Moon until the next one.
So that's always close to (0.25 x 29.53) = 7.38 days ... essentially 1 week.
Answer:
The required answer is 35100