All categories

3 years ago

The mass percent of element X

Chemistry

1 answer:

WINSTONCH [101]3 years ago

7 0

Answer:

128.4 g

Explanation:

Step 1: Given data

Mass percent of element X in X(NO₃)₂: 52.55%

Mass of the element X in the sample: 67.50 g

Step 2: Determine the total mass of the sample

The mass percent of element X in X(NO₃)₂ is 52.55%, that is, there are 52.55 g of X every 100 g of X(NO₃)₂. Then, the mass of X(NO₃)₂ that contains 67.50 g of X is:

67.50 g X × 100 g X(NO₃)₂/52.55 g X = 128.4 g X(NO₃)₂

You might be interested in

When silver nitrate is added to an aqueous solution of magnesium chloride, a precipitation reaction occurs that produces silver

Aloiza [94]

Answer:

103.62 g of AgCl.

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

2AgNO3 + MgCl2 —> 2AgCl + Mg(NO3)2

Step 2:

Determination of the mass of MgCl2 that reacted and the mass of AgCl produced from the balanced equation.

This is illustrated below:

Molar mass of MgCl2 = 24 + (2x35.5) = 95 g/mol

Mass of MgCl2 from the balanced equation = 1 x 95 = 95 g

Molar mass of AgCl = 108 + 35.5 = 143.5 g/mol

Mass of AgCl from the balanced equation = 2 x 143.5 = 287 g

Thus, from the balanced equation above,

95 g of MgCl2 reacted to produce 287 g of AgCl.

Step 3:

Determination of the mass of AgCl produced from the reaction of 34.3 g of MgCl2.

The mass of AgCl produced from the reaction can be obtained as follow:

Form the balanced equation above,

95 g of MgCl2 reacted to produce 287 g of AgCl.

Therefore, 34.3 g of MgCl2 will react to produce = (34.3 x 287)/95 = 103.62 g of AgCl.

Therefore, 103.62 g of AgCl were produced from the reaction.

8 0

4 years ago

What are the effects of global warming?

svp [43]

the effects are: temperature rises, water shortages, and increased fire threats

7 0

3 years ago

Base your answers to questions 69 through 72 on the information below and on your knowledge of chemistry.

evablogger [386]

Hydrazine has a higher boiling point than water because hydrazine exhibits a stronger intermolecular forces than water. Although both compounds exhibit hydrogen bonding which is a strong intermolecular force resulting to a high boiling point, hydrogen bonding is stronger in hydrazine. This is because in a hydrazine molecule, there are two atoms of nitrogen available for hydrogen bonding as compared to water which has only 1 oxygen atom for hydrogen bonding.

6 0

3 years ago

What volume of .100 M HCl is required to titrate .100 g of sodium bicarbonate to its equivalence point?

Karo-lina-s [1.5K]

The reaction is: HCl + Na HCO3 → NaCl + H2CO3, which is already balanced.

Then the molar ratios are 1 mol HCL : 1 mol NaHCO3

You know the mass of NaHCO3 is 0.100 g, then you can find the number of moles using the molar mass of NaHCO3

molar mass of NaHCO3 is 23 g/mol + 1 g/mol + 12g/mol + 3*16g/mol = 84 g/mol

And the number of moles is: 0,100 g / 84 g/mol = 0,0012 mol of NaHCO3.

Then, from the ratio 1:1, you know that, at the titration point, the number of moles of HCl is the same: 0,0012 mol of HCl.

Now from the fomula of molarity you have: M = #of moles / V in liters

=> V in liters = # of moles / M = 0.0012 mol / 0.100 M = 0.012 liters

Answer: 0.012 liters of HCL

6 0

4 years ago

Read 2 more answers

The partial pressure of cartbon dioxide in the atmgsphere is 0239 toer Caiculate the partial pressure in mm He and atm Rpund eac

Verizon [17]

Answer :

The pressure of carbon dioxide in the atmosphere in mmHg is 0.239mmHg.

The pressure of carbon dioxide in the atmosphere in atm is $3.14\times 10^{-4}atm$ .

Explanation :

The conversion used for pressure from torr to mmHg is:

1 torr = 1 mmHg

The conversion used pressure from torr to atm is:

1 atm = 760 torr

or,

$1torr=\frac{1}{760}atm$

As we are given the pressure of carbon dioxide in the atmosphere 0.239 torr. Now we have to determine the pressure of carbon dioxide in the atmosphere in mmHg and atm.

<u>Pressure in mmHg :</u>

As, $1torr=1mmHg$

So, $0.239torr=\frac{0.239torr}{1torr}\times 1mmHg=0.239mmHg$

Thus, the pressure of carbon dioxide in the atmosphere in mmHg is 0.239mmHg.

<u>Pressure in atm:</u>

As, $1torr=\frac{1}{760}atm$

So, $0.239torr=\frac{0.239torr}{1torr}\times \frac{1}{760}atm=3.14\times 10^{-4}atm$

Thus, the pressure of carbon dioxide in the atmosphere in atm is $3.14\times 10^{-4}atm$ .

3 0

3 years ago