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Nutka1998 [239]
3 years ago
13

The mass percent of element X

Chemistry
1 answer:
WINSTONCH [101]3 years ago
7 0

Answer:

128.4 g

Explanation:

Step 1: Given data

  • Mass percent of element X in X(NO₃)₂: 52.55%
  • Mass of the element X in the sample: 67.50 g

Step 2: Determine the total mass of the sample

The mass percent of element X in X(NO₃)₂ is 52.55%, that is, there are 52.55 g of X every 100 g of X(NO₃)₂. Then, the mass of X(NO₃)₂ that contains 67.50 g of X is:

67.50 g X × 100 g X(NO₃)₂/52.55 g X = 128.4 g X(NO₃)₂

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What is the molarity of a stock solution if 60 mL were used to make 150 ml<br>of a .5M solution? ​
olga2289 [7]

The molarity of the stock solution is 1.25 M.

<u>Explanation:</u>

We have to find the molarity of the stock solution using the law of volumetric analysis as,

V1M1 = V2M2

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M1 = 0.5 M

V2 = 60 ml

M2 = ?

The above equation can be rearranged to get M2 as,

M2 = $\frac{V1M1}{V2}

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4 0
3 years ago
What is the appropriate chemical formula for Iron(III) Sulfate? Sulfate is SO_4^2 Fe3SO4 O a . Fe2(SO4)3 O b. O c. Fe2SO4 O d. F
AnnyKZ [126]

<u>Answer:</u> The chemical formula of Iron (III) sulfate is Fe_2(SO_4)_3

<u>Explanation:</u>

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To form Fe^{3+} ion, this element will loose 3 electrons.

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By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for Iron (III) sulfate is Fe_2(SO_4)_3

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3 years ago
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