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alina1380 [7]
3 years ago
11

Is this line real or imaginary?

Chemistry
2 answers:
Pani-rosa [81]3 years ago
7 0

Answer:

What are you talking abt

Explanation:

podryga [215]3 years ago
6 0
Imaginary as there is no line
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SOMEONE HELP PLEASE 60 POINTS!!!!!!! IM TIMED TOO SO PLS
Sergeu [11.5K]

Explanation:

ooohhhh it's free points,,,thank you mwahhh hahahahahaha jokeee

sorry I don't have any ideas

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3 years ago
How would increased chlorofluorocarbons (CFCs) in the atmosphere affect the growth of vegetation throughout the world?
IgorC [24]
Chlorofluorocarbons are a class of organic compounds that were used as propellants in the late 20th century. The problem with CFC's is that they attack the ozone layer, breaking it down. The weakened ozone layer is not able to stop UV light from reaching the earth, so the amount of UV light reaching the earth increases. This results in increased temperatures, and the death of vegetation.

Therefore, the answer is B.
7 0
3 years ago
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Upal.
MissTica

Answer:

sodium

Explanation:

this is because sodium is neutral ....hence the pH formed will be 7

7 0
3 years ago
What is the change in internal energy for each of the following situations? 1. q-7.9 J out of the system and w 3.6 J done on the
adoni [48]

Answer:

A i. Internal energy ΔU = -4.3 J ii. Internal energy ΔU = -6.0 J B. The second system is lower in energy.

Explanation:

A. We know that the internal energy,ΔU = q + w where q = quantity of heat and w = work done on system.

1. In the above q = -7.9 J (the negative indicating heat loss by the system). w = 3.6 J (It is positive because work is done on the system). So, the internal energy for this system is ΔU₁ = q + w = -7.9J + 3.6J = -4.3 J

ii. From the question q = +1.5 J (the positive indicating heat into the system). w = -7.5 J (It is negative because work is done by the system). So, the internal energy for this system is ΔU₂ = q + w = +1.5J + (-7.5J) = +1.5J - 7.5J = - 6.0J

B. We know that ΔU = U₂ - U₁ where U₁ and U₂ are the initial and final internal energies of the system. Since for the systems above, the initial internal energies U₁ are the same, then we say U₁ = U. Let U₁ and U₂ now represent the final energies of both systems in A i and A ii above. So, we write ΔU₁ = U₁ - U and ΔU₂ = U₂ - U where ΔU₁ and ΔU₂ are the internal energy changes in A i and A ii respectively. Now from ΔU₁ = U₁ - U, U₁ = ΔU₁ + U and U₂ = ΔU₂ + U. Subtracting both equations U₁ - U₂ = ΔU₁ - ΔU₂

= -4.3J -(-6.0 J)= 1.7 J. Since U₁ - U₂ > 0 , U₂ < U₁ , so the second system's internal energy increase less and is lower in energy and is more stable.

8 0
3 years ago
When a strontium atom loses two electrons, it becomes a(n) _____ with a charge of _____?
Iteru [2.4K]
<span>When a strontium atom loses two electrons, it becomes a(n) cation with a charge of 2+.
when any neutral atom loses an electron it becomes cation that is positively charged ions and an ion gets the charge according to the number of electrons loses. And if an atom gains an electron it becomes anion that is negatively charged ions.</span>
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