Answer:
2 KCIO₃ → 2 KCI + 3 O₂
Explanation:
A chemical equation is balanced when the number of atoms of each element is equal on both sides of the equation.
You have already identified the initial number of atoms of each element on both sides of the equation. As a rule of thumb, we balance the number of oxygen and hydrogen atoms last.
However, since all the other elements are already balanced, we shall start by balancing the number of oxygen atoms.
The lowest common multiple of 2 and 3 is 6. Thus, we shall ensure that both sides of the equation has 6 oxygen atoms.
2 KCIO₃ → KCI + 3 O₂
<u>Reactants</u>
K --- 2
C--- 2
I --- 2
O --- 6
<u>Products</u>
K --- 1
C --- 1
I --- 1
O --- 6
Notice that number of K, C and I atoms on the left-hand side of the equation has also changed.
2 KCIO₃ → 2 KCI + 3 O₂
<u>Reactants</u>
K --- 2
C --- 2
I --- 2
O --- 6
<u>Products</u>
K --- 2
C --- 2
I --- 2
O --- 6
The equation is now balanced.
Answer:
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Explanation:
The unbalanced chemical equation with the corresponding phase for each substance is shown below:
Cu₍s₎ + H₂SO₄₍aq₎ → CuSO₄₍aq₎ + SO₂₍g₎ + H₂O₍l₎
The copper metal is solid, the sulfuric acid and copper sulfate are in aqueous solution. Water is in the liquid phase while sulfur dioxide is in the gas phase.
In order to obtain the balanced equation, we must ensure that the number of atoms present in the reactant side is equal to that in the product side. First, we list the elements involved and count their number on each side.
Reactant Product
1 Cu 1
2 H 2
1 S 2
4 O 5
To balance the equation, we need to have 2 moles of H₂SO₄ and 2 moles of H₂O. The balanced chemical equation is then:
Cu₍s₎ + 2H₂SO₄₍aq₎ → CuSO₄₍aq₎ + SO₂₍g₎ + 2H₂O₍l₎
Reactant Product
1 Cu 1
4 H 4
2 S 2
8 O 8
