(X^-3)^-5x^6 A. X^21 B. X^-21 C. X^48 D. X^-48
1 answer:
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Answer: a) +
= 1
b) The distance of two foci is 85.4 feet
c) Area = 3502.67 square feet
Step-by-step explanation: a) An ellipse has the equation in the form of:
+
= 1, where a is the horizontal axis and b is the vertical axis.
For the Statuary Hall, a = = 48.5 and b =
= 23, so the equation will be
+
= 1.
b) To determine the distance of the foci, we have to calculate 2c, where c is the distance between one focus and the center of the ellipse. To find c, as a, b and c create a triangle with a as hypotenuse:
=
c =
c = 42.7
The distance is 2c, so 2·42.7 = 85.4 feet.
The two foci are 85.4 feet apart.
c)The area of an ellipse is given by:
A = a.b.π
A = 48.5 · 23 · 3.14
A = 3502.67 ft²
The area of the floor room is 3502.67ft².