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FinnZ [79.3K]
3 years ago
6

If IM is reflected across the x-axis and then translated along the vector <4, 1>, in

Mathematics
1 answer:
taurus [48]3 years ago
7 0

Answer:

Final image L"M" will lie in the fourth quadrant.

Step-by-step explanation:

Coordinates of the ends of segment LM,

L  → (-3, 4)

M → (-3, 2)

Rule to reflect a point across x-axis is,

(x, y) → (x, -y)

By this rule, coordinates of the image point of L and M will be,

L(-3, 4) → L'(-3, -4)

M(-3, 2) → M'(-3, -2)

Further these image points are translated along the vector <4, 1>

Rule for this translation will be,

(x, y) → (x + 4, y + 1)

Now the image points of the points L' and M' will be,

L'(-3, -4) → L"(-3 + 4, -4 + 1)

             → L"(1, -3)

M'(-3, -2) → M"(-3 + 4, -2 + 1)

              → M"(1, -1)

Therefore, final image L"M" will lie in the fourth quadrant.

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3 years ago
Write answer in slope intercept form (3,-8); slope= -3
Slav-nsk [51]

Answer:

y=-3x-8

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Find x<br> 5[x^2]+5[x]-x^2-x=2004
a_sh-v [17]

The answer is either x=\frac{-1}{2}+\frac{1}{2}\sqrt{2005}\\ or x=\frac{-1}{2}+\frac{-1}{2}\sqrt{2005}

To solve: Let's solve your equation step-by-step.

5x2+5x−x2−x=2004

Step 1: Simplify both sides of the equation.

4x2+4x=2004

Step 2: Subtract 2004 from both sides.

4x2+4x−2004=2004−2004

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Step 3: Use quadratic formula with a=4, b=4, c=-2004.

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3 years ago
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