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aleksklad [387]
3 years ago
5

The value of a car is $30,000 and depreciates at a rate of 6.5% each year.

Mathematics
1 answer:
navik [9.2K]3 years ago
7 0

Answer:$20250

Step-by-step explanation:

6.5% of 30000

6.5/100 x 30000

(6.5 x 30000)/100

195000/100=1950

First year depreciation 30000-1950=28050

Second year=28050-1950=26100

Third year=26100-1950=24150

Fourth year=24150-1950=22200

Fifth year=22200-1950=20250

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I suppose the integral could be

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