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Neko [114]
3 years ago
13

PLEASE HELP AGAIN lol thank you :))

Chemistry
1 answer:
Annette [7]3 years ago
8 0
BBBBBBBBBBBBBBBBBBBBBBBBBBBBB
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The compound diborane can be used as a rocket propellant. What is the percent composition of boron in diborane (B2H6)? A. 22% B.
sveticcg [70]

Answer: E. 78%

Explanation:

Diborane (B2H6), a chemical compound made up of approximately 78% Boron and 22% Hydrogen.

4 0
3 years ago
Type the correct answer in the box. express your answer to three significant figures. an air mattress is filled with 0.55 moles
dmitriy555 [2]

385 L is the volume of the air mattress with 0.55 moles of air inside the mattress and a temperature of 295 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 3.5 kPa

V=?

n= 0.55 moles of air

T= 295K

R= 8.314 (L kPa/mol K)

Putting value in the given equation:

V= \frac{nRT}{P}  

V = \frac{(0.55 moles)(8.314 L kPa/mol k)(295 K)}{3.5 kPa}

V = 385.4132857 L

And whatever the significant figure is asked for, for example, 3 significant figures: the answer would be 385 litres.

Hence, 385.4132857 L is the volume of the air mattress.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

5 0
2 years ago
Structure of 2,6-diiodo-4-methyl-5-propylheptane​
ira [324]

Explanation:

2,6-Dibromo-4-isopropylphenol

2432-16-8

2,6-dibromo-4-propan-2-ylphenol

Phenol, 2,6-dibromo-4-(1-methylethyl)-

4-isopropyl-2,6-dibromophenol

5 0
3 years ago
Plants and animals depend on glucose (C6H12O6) as an energy source. Calculate the number of moles of each element in 1.25 mol C6
Aleksandr-060686 [28]

Answer:

15 mol.

Explanation:

trust

4 0
3 years ago
What is the initial temperature (°C) of a system that has the pressure decreased by 10 times while the volume increased by 5 tim
Ede4ka [16]

Answer:

300K

Explanation:

Given pressure of the system decreased by 10 times which means P_{2} =\frac{P_{1} }{10}

Given the volume of the system increased by 5 times which means V_{2} =5\times V_{1}

Given final temperature T_{2}=150K

Let the initial temperature be T_{1}

We know that PV=nRT

As n and R are constant \frac{PV}{T}=constant

\frac{P_{1}V_{1} }{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}

T_{1} =\frac{P_1V_1}{P_2V_2} T_{2}

T_{1} =2\times T_{2}

T1=300K

8 0
3 years ago
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