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AleksAgata [21]
3 years ago
13

Identify 5 basic examples of Solutions?

Chemistry
2 answers:
Elden [556K]3 years ago
7 0
Coffe
Gasoline
Water
Coffe
Apple juice
A solution is any liquid
katovenus [111]3 years ago
4 0

Answer:

Coffee

Tea

Juice

Bleach

Salt water

Explanation:

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Put 30,000,000,000 into scientific notation
Neko [114]
Your number in decimal form is
3,000,000
.
To get to standard scientific notation, we move the decimal point so there is only one non-zero digit in front of the decimal point.
So,
3,000,000
becomes
3.000,000
.
The trailing zeroes are not significant, so
3.000,000
becomes
3
.
We moved the decimal point six places, so the exponent is
6
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We moved the decimal point to the left, so the exponent is positive.
The exponential part is therefore
10
6
.
3,000,000=3 X10^6
8 0
3 years ago
Read 2 more answers
A student attempts to measure the specific heat capacity of an unknown liquid through repeated trials. She measures its specific
Goryan [66]

Answer:

2.13

Explanation:

4 0
3 years ago
An astronaut in her spacesuit weighs 300 lb on earth. What would her weight be on the moon?
Phantasy [73]
She would be 150 on the moon because the moon has half the mass of earth
6 0
2 years ago
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How many moles of CaCO3 are needed to react with 12.5 mol SO2​
grandymaker [24]
<h3><u>Answer;</u></h3>

= 12.5 Moles of CaSO3

<h3><u>Explanation</u>;</h3>

The reaction between CaCO3 and SO2 is given by the equation.

CaCO3(s) + SO2(g) → CaSO3(aq) + CO2(g)

The mole ratio between CaCO3 and SO2 is 1 : 1;

1 mole of CaCO3 reacts with 1 mole SO2 to form CaSO3 and CO2

Therefore;

<em>12.5 moles of SO2 will require 12.5 moles of CaSO3</em>

7 0
3 years ago
34. 3.15 mol of an unknown solid is placed into enough water to make 150.0 mL of solution. The solution's temperature increases
Digiron [165]

Answer:

ΔH = 2.68kJ/mol

Explanation:

The ΔH of dissolution of a reaction is defined as the heat produced per mole of reaction. We have 3.15 moles of the solid, to find the heat produced we need to use the equation:

q = m*S*ΔT

<em>Where q is heat of reaction in J,</em>

<em>m is the mass of the solution in g,</em>

<em>S is specific heat of the solution = 4.184J/g°C</em>

<em>ΔT is change in temperature = 11.21°C</em>

The mass of the solution is obtained from the volume and the density as follows:

150.0mL * (1.20g/mL) = 180.0g

Replacing:

q = 180.0g*4.184J/g°C*11.21°C

q = 8442J

q = 8.44kJ when 3.15 moles of the solid react.

The ΔH of the reaction is:

8.44kJ/3.15 mol

= 2.68kJ/mol

5 0
2 years ago
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