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umka2103 [35]
3 years ago
8

Balance this chemical equation

Chemistry
1 answer:
Papessa [141]3 years ago
7 0

Answer:

the chemical equation is balanced ❤

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Mason notices that his boat sinks lower in the water in a freshwater lake than in the ocean. what could explain this
tino4ka555 [31]

Answer:

Mason notices that his boat sinks lower into the water in a freshwater lake than in the ocean. What could explain this?

Explanation:

The freshwater has less density then the ocean!

6 0
3 years ago
60 grams of ice will require _____ calories to raise the temperature 1°C.
guajiro [1.7K]

Answer:

60 grams of ice will require 30.26 calories to raise the temperature 1°C.

Explanation:

The amount of heat (Q) to raise the temperature of 60.0 g of ice by 1°C can be calculated from:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat released or absorbed by the system.

m is the mass of the ice (m = 60.0 g).

c is the specific heat capacity of ice (c = 2.108 J/g.°C).

ΔT is the temperature difference (ΔT = 1.0 °C).

∴ Q = m.c.ΔT = (60.0 g)(2.108 J/g.°C)(1.0 °C) = 126.48 J.

<em>It is known that 1.0 cal = 4.18 J.</em>

<em>∴ Q = (126.48 J)(1.0 cal / 4.18 J) = 30.26 cal.</em>

7 0
3 years ago
An irregularly-shaped piece of copper (Cu) has a mass of 55.0 grams. What is the volume in cm³ of this piece of copper if its de
vredina [299]

Answer:

<h2>6.14 cm³</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question we have

volume =  \frac{55}{8.96}  \\  = 6.138392...

We have the final answer as

<h3>6.14 cm³</h3>

Hope this helps you

8 0
3 years ago
Which mixture is classified as a solution?
svlad2 [7]
Salt water is considered to be a solution
5 0
3 years ago
The Law of Conservation of Mass states that ____
Vaselesa [24]
I will mark you brainlist please help

1) A ball is thrown with the speed of 10 m/s from the 1st stair. The height of each stair is 10cm and the width is 15 cm. on which stair the ball will fall
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3 years ago
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