Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]
It's hard to tell where one set ends and the next starts. I think it's
A. 25, 36, 44, 51, 62, 77
B. 3, 3, 3, 7, 9, 9, 10, 14
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.
A. 25, 36, 44, 51, 62, 77
That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.
B. 3, 3, 3, 7, 9, 9, 10, 14
Average around 7, sigma around 4, within 2 sigma, seems ok.
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
Average around 20, sigma around 8, that 39 is hanging out there past two sigma. Let's reserve judgement and compare to the next one.
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Average around 74, sigma 8, seems very tight.
I guess we conclude C has the outlier 39. That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.
Answer: 2years, 5 months
Step-by-step explanation:
Principal, P = $6000
Rate, R = 3%
Interest, I = $450
Time, T =?
Simple Interest, I = P x T x R/ 100
making T, subject of formula
T = 100 x I/ P x T
Substituting the values into the equation,
T = 100 x 450/ 6000 x 3
T = 45000/ 18000
T = 2.5years = 2years, 5 months
The initial function is slope
=> slope = 7-1/6-0 = 6/6 = 1
Hope this helps you :)
Answer:
12
Step-by-step explanation:
You could actually list the numbers between (but not including) 45 and 58:
{46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57}. I count 12 numbers here.
