All categories

3 years ago

Point give away number 5!

Chemistry

2 answers:

777dan777 [17]3 years ago

6 0

Answer:

o.o

Explanation:

Leya [2.2K]3 years ago

5 0

thanksssssss

I like your pfp!!!!

You might be interested in

____________ limits or stops the growth of bacteria.

Kaylis [27]

Answer:

Vaccines

Explanation:

3 0

2 years ago

Read 2 more answers

What would be the formula for an alkane which contains 30 hydrogen atoms? C__H30 16 18 14 15

Sladkaya [172]

The formula would be C14H30.

6 0

3 years ago

Read 2 more answers

Determine the molality of a solution of methanol dissolved in ethanol for which the mole fraction of methanol is 0.135. Give you

Alja [10]

Answer: The molality of the solution is 0.11 m

Explanation:

We are given:

Mole fraction of methanol = 0.135

This means that 0.135 moles of methanol is present in 1 mole of a solution

Moles of ethanol = 1 - 0.135 = 0.865 moles

To calculate the mass for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of ethanol = 0.865 moles

Molar mass of ethanol = 46 g/mol

$0.865mol=\frac{\text{Mass of ethanol}}{46g/mol}\\\\\text{Mass of ethanol}=(0.865mol\times 46g/mol}=39.79g$

To calculate the molality of solution, we use the equation:

$Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

Where,

$m_{solute}$ = Given mass of solute (methanol) = 0.135 g

$M_{solute}$ = Molar mass of solute (methanol) = 32 g/mol

$W_{solvent}$ = Mass of solvent (ethanol) = 39.79 g

Putting values in above equation, we get:

$\text{Molality of methanol}=\frac{0.135\times 1000}{32\times 39.79}\\\\\text{Molality of methanol}=0.106m\approx 0.11m$

Hence, the molality of the solution is 0.11 m

6 0

3 years ago

27 Which energy conversion must occur in an operating electrolytic cell?

Vitek1552 [10]

 electrical energy to chemical energy

5 0

3 years ago

When 25.0 mL of a solution of 1.4 x 10-3 M silver nitrate is mixed with 60.0 mL of a solution of 7.5 x 10-4 M sodium chloride a)

LUCKY_DIMON [66]

Step one write the equation for dissociation of AgNO3 and NaCl

that is AgNO3-------> Ag+ + NO3-

NaCl--------> Na+ + Cl-
then find the number of moles of each compound
that is for AgNO3 = ( 1.4 x10^-3 ) x 25/1000= 3.5 x10^-5 moles
Nacl= (7.5 x10^-4)x 60/1000= 4.5 x10^-5 moles

from mole ratio the moles of Ag+= 3.5 x10^-5 moles and that of Cl-= 4.5 x10^-4 moles

then find the total volume of the mixture
that is 25ml + 60 Ml =85ml = 0.085 liters

The Ksp of Agcl = (Ag+) (cl-), let the concentration of Ag+ be represented by x and also the concentration be represented by x

ksp (1.8 x10^-10) is therefore= x^2

find the square root x=1.342 x10^-5

Ag+ in final mixture is = moles of Ag+/total volume - x
that is {(3.5 x10^-5)/0.085} - 1.342 x10^-5=3.98x10^-4

Cl- in the final mixture is =(4.5 x10^-5 /0.085) - 1.342 x10^-5= 5.16 x10^-4

4 0

3 years ago

Read 2 more answers